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anonymous

  • 5 years ago

The probability of an event occurring is 23/50. What are the odds that the event will occur?

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  1. anonymous
    • 5 years ago
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    if the probability in favor is p, then the odds in favor are \[\frac{p}{1-p}\] i.e. probabilty in favor divided by the probability against. in this case you get \[\frac{23}{27}\]

  2. anonymous
    • 5 years ago
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    think of it easy as 23 out of 50 chances to win and therefore 27 out of 50 to lose.

  3. amistre64
    • 5 years ago
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    the odds are 46%

  4. amistre64
    • 5 years ago
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    23/50 that it occurs. the odds that it WILL occur are 46% right?

  5. anonymous
    • 5 years ago
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    really? in that case i made a mistake, but i don't think so.

  6. anonymous
    • 5 years ago
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    oh no that is probability, not odds.

  7. amistre64
    • 5 years ago
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    ahhh... like saying 5 to 2 or something right?

  8. anonymous
    • 5 years ago
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    if the probability i win is \frac{2}{3}\] then the odds i win are two to one.

  9. anonymous
    • 5 years ago
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    \[\frac{p}{1-p}\]

  10. amistre64
    • 5 years ago
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    chance occur to chance not occur is an odd then right?

  11. anonymous
    • 5 years ago
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    right like saying 5 to 2. exactly

  12. anonymous
    • 5 years ago
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    yes right.

  13. anonymous
    • 5 years ago
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    not really used much in math, but sometimes. gamblers' ruin problem. used mostly at the track.

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