anonymous
  • anonymous
multiply: (1+2i)(2-i)
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
i am so lost on where to start with this problem
anonymous
  • anonymous
this is 8th grade math right?
anonymous
  • anonymous
intermediate algebra. would i answer it the same if it was 'x' instead of 'i'

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

watchmath
  • watchmath
You just apply the distributive property \(1\cdot 2+1\cdot (-i)+2i\cdot2+2i\cdot (-i)\)
anonymous
  • anonymous
Just foil it out like you would normally (treat the i kinda like a variable) and just remember that if you have an \(i^2\) that equals -1
anonymous
  • anonymous
oh okay!! thanks! i wasnt sure if i just fouil like normal. the "i" threw me off!
anonymous
  • anonymous
don't be scared of letters. They're actually much easier to work with than numbers because you don't have to plug them into your calculator ;)
anonymous
  • anonymous
thank you. i got 2-1i+4i-2i so far
anonymous
  • anonymous
2+3i-2i as the answer
watchmath
  • watchmath
\(2-1i+4i-2i^2\). Now you can use \(i^2=-1\)
anonymous
  • anonymous
2+3i-2i^2 ..which would be 2+3i+2
watchmath
  • watchmath
good! you can combine 2+2 as well

Looking for something else?

Not the answer you are looking for? Search for more explanations.