multiply: (1+2i)(2-i)

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multiply: (1+2i)(2-i)

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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i am so lost on where to start with this problem
this is 8th grade math right?
intermediate algebra. would i answer it the same if it was 'x' instead of 'i'

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Other answers:

You just apply the distributive property \(1\cdot 2+1\cdot (-i)+2i\cdot2+2i\cdot (-i)\)
Just foil it out like you would normally (treat the i kinda like a variable) and just remember that if you have an \(i^2\) that equals -1
oh okay!! thanks! i wasnt sure if i just fouil like normal. the "i" threw me off!
don't be scared of letters. They're actually much easier to work with than numbers because you don't have to plug them into your calculator ;)
thank you. i got 2-1i+4i-2i so far
2+3i-2i as the answer
\(2-1i+4i-2i^2\). Now you can use \(i^2=-1\)
2+3i-2i^2 ..which would be 2+3i+2
good! you can combine 2+2 as well

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