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The questions is do I add the choices together or multiply them?
Well to assemble an outfit you must pick 1 jean, 1 sweater, and 1 shirt. So if you must do 3 different tasks to complete a job (make an outfit) you must multiply the number of different ways you can do each task.
It's 165 combinations possible right? Or did I mess up somewhere?
The only time you add is if you can do a job by doing one task OR another task. Then you would add the different ways you can do task1 and the different ways you can do task2. But if you must do task1 AND task2 then you multiply.
That seems like too many.
There are 3 different ways you can pick your jeans. There are 3 different ways you can pick your sweater. There are 5 different ways you can pick your shirt. The number of ways you can pick a jean AND a sweater AND a shirt is: 3 * 3 * 5 = 45
Unless you are suggesting you can have a shirt and no sweater also, or a sweater and no shirt
I assume you must have pants at least ;)
I'm not, but the problem was suggesting that it was an equation using combinations, where as you're using the counting principle. ~ Good assumption.
Or at least I think you are.
Well I am using combinations: 3C1 * 3C1 * 5C1 = 45 But if you are going to have sweaters and no shirts or shirts and no sweaters too it'd be 3C1 * 3C1 * 5C1 + 3C1 * 3C1 + 3C1 * 5C1 = 69
Assuming you must have at least jeans and either a shirt or a sweater (or both) and not more than one of any kind of thing.
I'm not wearing two pairs of pants.. that's just silly.
Well the sheets I'm given to work out are hardly ever right and barely give any information on how to solve the darn thing, so it could be suggesting that you are wearing two pants at once, would get rather hot if you ask me, but it could happen.
I dunno. Sounds hotter to not be wearing pants ;p
To each his own, I suppose.