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anonymous
 5 years ago
Solve using the quadratic forumula.
3x^2 + x  4 = 0
anonymous
 5 years ago
Solve using the quadratic forumula. 3x^2 + x  4 = 0

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Do you know the quadratic formula? \[b \pm \sqrt{b ^{2}4ac}/2a\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Then it's just a matter of plugging in the values and simplifying.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.03x^2+4x3x4=0 (x1)(3x+4)=0

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I understand how to substitute everything in, but from there I am unsure how to simplify 1 ± 12−4*3*4−−−−−−−√

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Work on the square root part first. \[\sqrt{1^{2}4*3*4}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0You missed a couple things in the sqrt. \[1^{2}=1\] 4*3*4=48 1(48)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Get that? So it's \[\sqrt{1+48}=\sqrt{49}=7\] So, \[(1 \pm 7)/6\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Thank you very much! That makes much more sense now. Once again, thanks!
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