Solve using the quadratic forumula. 3x^2 + x - 4 = 0

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Solve using the quadratic forumula. 3x^2 + x - 4 = 0

Mathematics
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Do you know the quadratic formula? \[-b \pm \sqrt{b ^{2}-4ac}/2a\]
Then it's just a matter of plugging in the values and simplifying.
3x^2+4x-3x-4=0 (x-1)(3x+4)=0

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Other answers:

x=1,-4/3
I understand how to substitute everything in, but from there I am unsure how to simplify -1 ± 12−4*3*4−−−−−−−√
-1 +/- sqrt -48
a=3,b=1, c=-4
Work on the square root part first. \[\sqrt{1^{2}-4*3*-4}\]
You missed a couple things in the sqrt. \[1^{2}=1\] 4*3*-4=-48 1-(-48)
Get that? So it's \[\sqrt{1+48}=\sqrt{49}=7\] So, \[(1 \pm 7)/6\]
Thank you very much! That makes much more sense now. Once again, thanks!
np.

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