anonymous
  • anonymous
find the area between the curves. y=log x y=x x=1 x=10
Mathematics
jamiebookeater
  • jamiebookeater
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amistre64
  • amistre64
yay!! an easy one :)
amistre64
  • amistre64
let me draw a pic to see if we got the right interpretation
amistre64
  • amistre64
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amistre64
  • amistre64
we integrate y=x between 1 and 10 then subtract y = log(x) between 1 and 10
amistre64
  • amistre64
\[\int\limits_{1}^{10} (x - \log(x)). dx\]
amistre64
  • amistre64
x^2 x ---- - ----- from [1,10] right? 2 log(x)
anonymous
  • anonymous
yes fro [1,10] and thanks for the graph!
amistre64
  • amistre64
x^2/2 = 100/2 - 1/2 = 99/2 99/2 - (10/log(10) - 1/log(1)) 99/2 - (10 - 1/0).... lol; lookslike I forgot how to int my log
anonymous
  • anonymous
thank you so much!
amistre64
  • amistre64
libraries closing on me so good luck with this one :)
anonymous
  • anonymous
can you please help me with my other questiones i posted :(
amistre64
  • amistre64
in about 10 minutes maybe; if they aint answered yet... gotta move to a new location :)
anonymous
  • anonymous
okay i will wait thanks!
amistre64
  • amistre64
log(x) = ln(x)/ln(10) 1/ln(10) is a constant so that gets put to the side for later int(ln(x)) = x(ln(x) - 1) xlnx - x ------- from 1,10 ln(10) 99/2 - [(10- 10/ln(10)) - (-1/ln(10))] is what i get

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