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anonymous
 5 years ago
find the area between the curves.
y=log x
y=x
x=1
x=10
anonymous
 5 years ago
find the area between the curves. y=log x y=x x=1 x=10

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amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1let me draw a pic to see if we got the right interpretation

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1we integrate y=x between 1 and 10 then subtract y = log(x) between 1 and 10

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1\[\int\limits_{1}^{10} (x  \log(x)). dx\]

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1x^2 x    from [1,10] right? 2 log(x)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yes fro [1,10] and thanks for the graph!

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1x^2/2 = 100/2  1/2 = 99/2 99/2  (10/log(10)  1/log(1)) 99/2  (10  1/0).... lol; lookslike I forgot how to int my log

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1libraries closing on me so good luck with this one :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0can you please help me with my other questiones i posted :(

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1in about 10 minutes maybe; if they aint answered yet... gotta move to a new location :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0okay i will wait thanks!

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1log(x) = ln(x)/ln(10) 1/ln(10) is a constant so that gets put to the side for later int(ln(x)) = x(ln(x)  1) xlnx  x  from 1,10 ln(10) 99/2  [(10 10/ln(10))  (1/ln(10))] is what i get
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