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anonymous
 5 years ago
find the volume of the solid obtained by rotating the region lying between the curves around the yaxis.
y=sinx
y=e^x
x=pi/2
x=pi
anonymous
 5 years ago
find the volume of the solid obtained by rotating the region lying between the curves around the yaxis. y=sinx y=e^x x=pi/2 x=pi

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watchmath
 5 years ago
Best ResponseYou've already chosen the best response.0\(\int_{\pi/2}^{\pi }2\pi x(e^x\sin x)\,dx\)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0can you help me with the steps?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1the graph doesnt makes sense ......

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1you appear to have a boundary between boundaries

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1or, that means that you spin it around the y axis; the part that is between ..got it

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1if so; shelling is fine; 2pi {S} (xe^x  xsin(x)) dx ; [pi/2, pi]

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1but it might be uglier than the disc method to integrate

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1e^x =y x = ln(y); is ln^2(y) easy to integrate? havent tried it meself lol

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1http://www.wolframalpha.com/input/?i=int%28pi%28ln%28y%29%29^2%29dy+from+0+to+1 says its 2pi for that bit :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i have couple more review questions can you help me amistre64?
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