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anonymous

  • 5 years ago

find the volume of the solid obtained by rotating the region lying between the curves around the y-axis. y=sinx y=e^x x=pi/2 x=pi

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  1. watchmath
    • 5 years ago
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    \(\int_{\pi/2}^{\pi }2\pi x(e^x-\sin x)\,dx\)

  2. anonymous
    • 5 years ago
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    can you help me with the steps?

  3. amistre64
    • 5 years ago
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    the graph doesnt makes sense ......

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  4. amistre64
    • 5 years ago
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    you appear to have a boundary between boundaries

  5. amistre64
    • 5 years ago
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    or, that means that you spin it around the y axis; the part that is between ..got it

  6. amistre64
    • 5 years ago
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  7. amistre64
    • 5 years ago
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    if so; shelling is fine; 2pi {S} (xe^x - xsin(x)) dx ; [pi/2, pi]

  8. amistre64
    • 5 years ago
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    but it might be uglier than the disc method to integrate

  9. amistre64
    • 5 years ago
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    e^x =y x = ln(y); is ln^2(y) easy to integrate? havent tried it meself lol

  10. amistre64
    • 5 years ago
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    http://www.wolframalpha.com/input/?i=int%28pi%28ln%28y%29%29^2%29dy+from+0+to+1 says its 2pi for that bit :)

  11. amistre64
    • 5 years ago
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    thnx :)

  12. anonymous
    • 5 years ago
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    i have couple more review questions can you help me amistre64?

  13. amistre64
    • 5 years ago
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    i can...maybe

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