find the volume of the solid obtained by rotating the region lying between the curves around the y-axis. y=sinx y=e^x x=pi/2 x=pi

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find the volume of the solid obtained by rotating the region lying between the curves around the y-axis. y=sinx y=e^x x=pi/2 x=pi

Mathematics
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\(\int_{\pi/2}^{\pi }2\pi x(e^x-\sin x)\,dx\)
can you help me with the steps?
the graph doesnt makes sense ......
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you appear to have a boundary between boundaries
or, that means that you spin it around the y axis; the part that is between ..got it
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if so; shelling is fine; 2pi {S} (xe^x - xsin(x)) dx ; [pi/2, pi]
but it might be uglier than the disc method to integrate
e^x =y x = ln(y); is ln^2(y) easy to integrate? havent tried it meself lol
http://www.wolframalpha.com/input/?i=int%28pi%28ln%28y%29%29^2%29dy+from+0+to+1 says its 2pi for that bit :)
thnx :)
i have couple more review questions can you help me amistre64?
i can...maybe

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