anonymous
  • anonymous
how do you integrate (x^9)(cos(x^5))?
Mathematics
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
\[intx ^{9}cosx ^{5}dx. \]
anonymous
  • anonymous
Possibly integration by parts
anonymous
  • anonymous
i realize that, but should i don't know what values to assign for u and dv. should i substitute before i even use integration by parts?

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anonymous
  • anonymous
Try x^9 as u
anonymous
  • anonymous
((x^10)/10)(-sinx(x^5))
anonymous
  • anonymous
What is that Nick, like the teacher says, show your work.
anonymous
  • anonymous
okay Integrate (x^9)we get (x^9+1)/(9+1) intregrate cos(x^5) we get -sin(x^5)
anonymous
  • anonymous
But there is a rule, the two x quantities are multiplied, so you can't integrate straight out, right?
anonymous
  • anonymous
yeah, so you integrate by parts.
anonymous
  • anonymous
yes
anonymous
  • anonymous
substituting u for x^9 doesn't seem to work chaguanas ...
anonymous
  • anonymous
Check this I haven't done integration by parts in a while\[x ^{9}\cos x ^{5}-45x ^{5}\sin x ^{5}\]
anonymous
  • anonymous
+C
watchmath
  • watchmath
http://www.wolframalpha.com/input/?i=integral+x^9*cos%28x^5%29+dx
watchmath
  • watchmath
wolframalpha will give you the steps as well.
anonymous
  • anonymous
hold on are you sure that the integral of cos x^5 is is -sin x^5 - try differentiating -sin x^5.
anonymous
  • anonymous
Yeah, mine is wrong, see the wolfram watchmath put up. That was the u sub that ecollison was talking about, I missed that.
anonymous
  • anonymous
watchmath thanks! the link was right
anonymous
  • anonymous
But please explain the u sub, they didn't account for the x^9 fully.
anonymous
  • anonymous
u=x^5 not x^9
anonymous
  • anonymous
lols

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