how do you integrate (x^9)(cos(x^5))?

At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions.

A community for students.

how do you integrate (x^9)(cos(x^5))?

Mathematics
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions

\[intx ^{9}cosx ^{5}dx. \]
Possibly integration by parts
i realize that, but should i don't know what values to assign for u and dv. should i substitute before i even use integration by parts?

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

Try x^9 as u
((x^10)/10)(-sinx(x^5))
What is that Nick, like the teacher says, show your work.
okay Integrate (x^9)we get (x^9+1)/(9+1) intregrate cos(x^5) we get -sin(x^5)
But there is a rule, the two x quantities are multiplied, so you can't integrate straight out, right?
yeah, so you integrate by parts.
yes
substituting u for x^9 doesn't seem to work chaguanas ...
Check this I haven't done integration by parts in a while\[x ^{9}\cos x ^{5}-45x ^{5}\sin x ^{5}\]
+C
http://www.wolframalpha.com/input/?i=integral+x^9*cos%28x^5%29+dx
wolframalpha will give you the steps as well.
hold on are you sure that the integral of cos x^5 is is -sin x^5 - try differentiating -sin x^5.
Yeah, mine is wrong, see the wolfram watchmath put up. That was the u sub that ecollison was talking about, I missed that.
watchmath thanks! the link was right
But please explain the u sub, they didn't account for the x^9 fully.
u=x^5 not x^9
lols

Not the answer you are looking for?

Search for more explanations.

Ask your own question