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anonymous

  • 5 years ago

least common multiple for 12,32, 42

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  1. anonymous
    • 5 years ago
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    So what number can all of these numbers be multiplied by another number so that they all get the same number?

  2. anonymous
    • 5 years ago
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    i dont know thats why i asked you guys and girls

  3. anonymous
    • 5 years ago
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    GAWD im typing random things into my calc and it looks like the only way to find it is to multiply them all together (: so 12 * 32 * 42 = 16128 So thats your least common multiple i think..

  4. anonymous
    • 5 years ago
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    thats not right it is 672

  5. anonymous
    • 5 years ago
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    ohhhh.... :P thanks! lol sorry about that mike (:

  6. anonymous
    • 5 years ago
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    you sure rsvitale

  7. anonymous
    • 5 years ago
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    you want the least positive integer that is a integer multiple of all of the arguments

  8. anonymous
    • 5 years ago
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    thank you

  9. anonymous
    • 5 years ago
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    yep im sure do you want to know how to find it?

  10. anonymous
    • 5 years ago
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    please

  11. anonymous
    • 5 years ago
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    yes

  12. anonymous
    • 5 years ago
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    ok you can start by taking the largest integer in the argument. You multiply it by 1 and see if the other numbers divide evenly into the result. If they do you are done and 1*largest is your least common multiple. If not you multiply by 2 and check if the other two divide evenly in. You repeat this until you find an integer that all arguments divide evenly into, and the first integer that this happens for is your least common multiple. So in your example 42*16 is the first integer multiple of the largest number that all arguments divide evenly into.

  13. anonymous
    • 5 years ago
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    does this make sense?

  14. anonymous
    • 5 years ago
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    whats an interger?

  15. anonymous
    • 5 years ago
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    integers are 0,1,-1,2,-2,3,-3,4,-4.... positive integers are 1,2,3,4,5,6... you are using positive integers here.

  16. anonymous
    • 5 years ago
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    they are whole numbers

  17. anonymous
    • 5 years ago
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    thank you\

  18. anonymous
    • 5 years ago
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    yep :)

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