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Well without it being equal to something you can't really 'solve' it...

no there's a way to solve it because someone got the answer but i dont know what it is

so what would the answer be and how would you get that answer?

Is this the expression?
\[(6x-10) \div {{9x - 15} \over 21}\]

no.. 6x - 10 is over 7, but everything else is right

Though you do need to stipulate that x cannot be equal to 5/3.

one question.. how did you get both denominators 7?

oh wait. I'm wrong.

Forgot I factored a 3 from the top and bottom of the fraction on the right.

thx .can you help me with another problem?

maybe

Heres the problem...8-y over y squared + 4 minus y - 2 over y squared + 4

\[{{8-y} \over y^2+ 4} - {{y-2} \over y^2+ 4} \]
That?

yah. how did u do that but anyway how do u solve it??

Well they are over a common denominator already so just subtract the numerators.

what answer would you get?