how do you solve 6x-10 over 7 divided by 9x-15 over 21?

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how do you solve 6x-10 over 7 divided by 9x-15 over 21?

Mathematics
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Well without it being equal to something you can't really 'solve' it...
no there's a way to solve it because someone got the answer but i dont know what it is
it can be reduced, simplified; but not really solved; its always gonna have an x in it unless that x factors out

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so what would the answer be and how would you get that answer?
the other option is to plot the points on a graph that result from inputing values of x and the graph becomes the solution.... but without knowing tha tthis is a function with respect to x its rather redundant
Is this the expression? \[(6x-10) \div {{9x - 15} \over 21}\]
no.. 6x - 10 is over 7, but everything else is right
\[{{6x-10} \over 7}\div {{9x - 15} \over 21}\]\[=2({{3x-5} \over 7}) \div 3({{3x-5} \over 7})\]\[={{2({{3x-5} \over 7})} \over {3({{3x-5} \over 7})}}\]\[ = {2 \over 3}\]
Though you do need to stipulate that x cannot be equal to 5/3.
one question.. how did you get both denominators 7?
oh wait. I'm wrong.
\[{{6x-10} \over 7}\div {{9x - 15} \over 21}\]\[=2({{3x-5} \over 7}) \div {3 \over 3}({{3x-5} \over 7})\]\[={{2({{3x-5} \over 7})} \over {1({{3x-5} \over 7})}} = 2,\ \forall x \ne {5 \over 3} \]
Forgot I factored a 3 from the top and bottom of the fraction on the right.
thx .can you help me with another problem?
maybe
Heres the problem...8-y over y squared + 4 minus y - 2 over y squared + 4
It would be very helpful if you would write these up in the equation editor because there are a number of ways to interpret what you wrote there.
oh i didn't know you could do that. because I'm kind of new to this website ....... 8-y/y squared + 4 minus y-2/y squared + 4? does that make a little more sense because I don't know how to do exponents so I just wrote it out
\[{{8-y} \over y^2+ 4} - {{y-2} \over y^2+ 4} \] That?
yah. how did u do that but anyway how do u solve it??
Well they are over a common denominator already so just subtract the numerators.
what answer would you get?

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