Find \[\frac{d^2y}{dx^2}\] at t=2, given: \[x=\sqrt{t}\quady=\sqrt{t-1}

Find \[\frac{d^2y}{dx^2}\] at t=2, given: \[x=\sqrt{t}\quady=\sqrt{t-1}

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Sorry, forgot the closing brackets:
\[x=\sqrt{t}\quad y=\sqrt{t-1}\]

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