How does \[\sum_{x=1}^{\infty}(\frac{1}{n})^{2} = \frac{pi^2}{6}\]

How does \[\sum_{x=1}^{\infty}(\frac{1}{n})^{2} = \frac{pi^2}{6}\]

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See 'The Basel Problem'

I saw it.

Oh, I forgot, you're the little kid who hates/is jealous of me.

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