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series of natural numbers

But, I no get (k+1) part

proving that if its true for one step; its true for every step

for me you have to identify whta is the successor of 1, and it is 0, so 1 is the successor of k

oops sorry

So, if n=1 is true, then (k+1) should be true?

No.

you havent really asked that detailed of a question; youre keeping secrets

Have you seen a domino effect? that's how you should think about induction.

Oops, didn't know you needed example. I sorry :) I give you example :) One moment, please

1 + 2 + 3 + . . . + n = ½n(n + 1)

n(n+1)
------ ah yes
2

gausses fame..

[Oh fun fact that isn't why Gauss is famous]

n=2; 1+2 = 3 ; 2(2+1)/2 = 3

............ THAT GREAT IDEA!!!!! :DDDDD

its why I know gauss tho lol

n = 3; 1+2+3 = 6 ; 3(3+1)/2 = 12/2 = 6

Gauss field equations

I think the second word of "assume" shouldn't be there.

It shouldn't, lazy copy and past, ugh.... sorry.

paste*. I should have used
\[\implies \] to start that line.