anonymous
  • anonymous
limit of 3x^3+ln(x)/x+3x^2 as x approaches infinity.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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amistre64
  • amistre64
maybe a salnt asymp?
anonymous
  • anonymous
? \[\frac{3x^3+ln(x)}{x+3x^2}\]
amistre64
  • amistre64
slant even

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More answers

anonymous
  • anonymous
saint asymptote, the patron saint of division
amistre64
  • amistre64
otherwise i think its just inf
anonymous
  • anonymous
\[3x^3+\ln(x)/x+2x^3\] typo'd sorry, dunno if that makes a difference.
amistre64
  • amistre64
y = 3x might be the slant..
amistre64
  • amistre64
it does lol
amistre64
  • amistre64
3/2
anonymous
  • anonymous
I'm bad at limits. Haha any help is greatly appreciated.
amistre64
  • amistre64
the infinity limits are gona be at the horizontal asymps if they exist
anonymous
  • anonymous
still infinity
amistre64
  • amistre64
i think the ln(x)/x^3 goes to zero...
anonymous
  • anonymous
oh i see it is \[\frac{3x^3+ln(x)}{x+2x^3}\] my mistake i misread it. amistre right, 3/2
amistre64
  • amistre64
http://www.wolframalpha.com/input/?i=lim{x+to+infinity}lnx%2Fx^3 im right lol
anonymous
  • anonymous
yes you are right of course. ration of leading coefficients.
anonymous
  • anonymous
ratio too
amistre64
  • amistre64
ration? now you are even typing like me ;)
anonymous
  • anonymous
How did you find that? How would you cancel out the natural log? I'm still kinda confused...
amistre64
  • amistre64
the log tends to slow down at inifinty; so the x^3 takes over and goes to 0
anonymous
  • anonymous
Ahh and then ratio of coefficients. Got it. Thanks!
amistre64
  • amistre64
a the ends; log(x) is pretty much a straight line
anonymous
  • anonymous
log grows slower than ANY polynomial, so you can ignore it safely
anonymous
  • anonymous
Right, right, I'm in compsci. We covered that. Should have remembered. Thanks so much! This was the first question I asked, how do I close this question?
amistre64
  • amistre64
you cant, its exists now forever in the ether of the cosmos ;)
anonymous
  • anonymous
That's... Unfortunate.
anonymous
  • anonymous
lord i hope not with all my wrong answers!
amistre64
  • amistre64
if you swear alot they might delete it lol

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