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anonymous

  • 5 years ago

limit of 3x^3+ln(x)/x+3x^2 as x approaches infinity.

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  1. amistre64
    • 5 years ago
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    maybe a salnt asymp?

  2. anonymous
    • 5 years ago
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    ? \[\frac{3x^3+ln(x)}{x+3x^2}\]

  3. amistre64
    • 5 years ago
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    slant even

  4. anonymous
    • 5 years ago
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    saint asymptote, the patron saint of division

  5. amistre64
    • 5 years ago
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    otherwise i think its just inf

  6. anonymous
    • 5 years ago
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    \[3x^3+\ln(x)/x+2x^3\] typo'd sorry, dunno if that makes a difference.

  7. amistre64
    • 5 years ago
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    y = 3x might be the slant..

  8. amistre64
    • 5 years ago
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    it does lol

  9. amistre64
    • 5 years ago
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    3/2

  10. anonymous
    • 5 years ago
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    I'm bad at limits. Haha any help is greatly appreciated.

  11. amistre64
    • 5 years ago
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    the infinity limits are gona be at the horizontal asymps if they exist

  12. anonymous
    • 5 years ago
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    still infinity

  13. amistre64
    • 5 years ago
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    i think the ln(x)/x^3 goes to zero...

  14. anonymous
    • 5 years ago
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    oh i see it is \[\frac{3x^3+ln(x)}{x+2x^3}\] my mistake i misread it. amistre right, 3/2

  15. amistre64
    • 5 years ago
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    http://www.wolframalpha.com/input/?i=lim {x+to+infinity}lnx%2Fx^3 im right lol

  16. anonymous
    • 5 years ago
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    yes you are right of course. ration of leading coefficients.

  17. anonymous
    • 5 years ago
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    ratio too

  18. amistre64
    • 5 years ago
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    ration? now you are even typing like me ;)

  19. anonymous
    • 5 years ago
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    How did you find that? How would you cancel out the natural log? I'm still kinda confused...

  20. amistre64
    • 5 years ago
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    the log tends to slow down at inifinty; so the x^3 takes over and goes to 0

  21. anonymous
    • 5 years ago
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    Ahh and then ratio of coefficients. Got it. Thanks!

  22. amistre64
    • 5 years ago
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    a the ends; log(x) is pretty much a straight line

  23. anonymous
    • 5 years ago
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    log grows slower than ANY polynomial, so you can ignore it safely

  24. anonymous
    • 5 years ago
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    Right, right, I'm in compsci. We covered that. Should have remembered. Thanks so much! This was the first question I asked, how do I close this question?

  25. amistre64
    • 5 years ago
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    you cant, its exists now forever in the ether of the cosmos ;)

  26. anonymous
    • 5 years ago
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    That's... Unfortunate.

  27. anonymous
    • 5 years ago
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    lord i hope not with all my wrong answers!

  28. amistre64
    • 5 years ago
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    if you swear alot they might delete it lol

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