find the cartesian equation of r = 8 sin thet + 8 cos theta

- anonymous

find the cartesian equation of r = 8 sin thet + 8 cos theta

- Stacey Warren - Expert brainly.com

Hey! We 've verified this expert answer for you, click below to unlock the details :)

- schrodinger

I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!

- amistre64

its a circle centered at the irigin of radius 8 maybe?

- anonymous

\[r =\sqrt{x ^{2}+y ^{2}}\]

- amistre64

polars and parametrics aint my strong point ;)

Looking for something else?

Not the answer you are looking for? Search for more explanations.

## More answers

- anonymous

youre good at vectors :)

- amistre64

yep, I can point at things all day lol

- anonymous

haha, and good at planes

- anonymous

maybe youre good at visualizing things?

- amistre64

im pretty good at visualizing stuff

- anonymous

ok we can use x = r cos theta, and y = r sin theta,

- anonymous

so multiply both sides by r

- amistre64

spinning polars tho.....not so much; aint had the practice

- anonymous

\[\sin \theta =x/r\]

- anonymous

ive read the vector stuff, it just wont stick. for some reason

- amistre64

polars are just vector equations at heart :)

- anonymous

i dont see that

- amistre64

r = magnitude; are the components

- amistre64

r is the basi set up

- anonymous

those are the cartesian components you mean

- amistre64

in the plane, yes

- amistre64

but polars define length(r) whih is the magnitude of a vector; and the angles are the x and y components of a vector

- amistre64

a vector function simply defines a curve or surface generated by the parametric equations for the vector components from teh origin

- amistre64

and that is all a polar equation is

- anonymous

come again, parametric equation for the vector components (the cartesian components?)

- amistre64

(r,t) is a polar equation right? (radius,theta)
this tells you how far to turn and how far to move

- amistre64

thats all a vector is; an arrow indicating direction and length

- anonymous

ok , lets use th for theta

- anonymous

ok , so say again your statement

- amistre64

which one lol

- amistre64

r is the vector equivalent of a polar equation (r,th)

- amistre64

or simpy

- anonymous

vector , as in the cartesian components of the vector

- amistre64

yes

- amistre64

the point P(x,y) is the same as defining a vector from the origin as

- amistre64

the vector is an arrow pointing to the point

- anonymous

right, that sometimes confuses me

- anonymous

we write < x,y> for a vector, and P(x,y) for a point

- amistre64

sometimes they write a vector as v(x,y) which confuses tha tmatter; i prefer the convention of just making it pointy to indicate its an arrow :)

- anonymous

right, i like to distinguish between points (n tuples) and vectors

- myininaya

cantorset i posted a proof for your viewing sorry it took me awhile to respond

- anonymous

i cant find it, one sec

- myininaya

k

Looking for something else?

Not the answer you are looking for? Search for more explanations.