anonymous
  • anonymous
solve (3x+7)^1/2=x-1
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
6
gw2011
  • gw2011
(3x+7)^1/2 = x-1 Square both sides since (3x+7)^1/2 is a square root 3x+7 = (x-1)^2 3x+7 = x^2-2x+1 0 = x^2-5x-6 I will rewrite this equation to get: x^2-5x-6 = 0 (x-6)(x+1) = 0 x-6 = 0 x = 6 x+1 = 0 x = -1 The two possible solutions are x=6 and x=-1 Now you need to substitute these values to see what the solution really is [(3)(6)+7]^1/2 = 6-1 (18+7)^1/2 = 6-1 (25)^1/2 = 6-1 5 = 5 which is a true statement and, therefore, x=6 is true (valid) [(3)(-1)+7]^1/2 = -1-1 (-3+7)^1/2 = -1-1 (4)^1/2 = -1-1 2 is not equal to -2 and, therefore, x=-1 is not true (not valid) Therefore, the answer is x=6

Looking for something else?

Not the answer you are looking for? Search for more explanations.