anonymous
  • anonymous
A particle moves under a hypothetical force so that its velocity vector is v= . Find its radial acceleration...Please help...
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
whata hard bout that?
anonymous
  • anonymous
acceleration is the derivative of velocity with respect to time
anonymous
  • anonymous
assuming k is a constant

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anonymous
  • anonymous
\[a = < k \frac{d}{dt} ( tcos(t)) , k \frac{d}{dt} ( tsin(t) ) > \]
anonymous
  • anonymous
k can be factored out of the vector, and it will just provide a scalar multiple
anonymous
  • anonymous
\[a = k < ( \cos(t) -tsin(t)) , (\sin(t) + tcos(t)) > \]
anonymous
  • anonymous
by product rules
anonymous
  • anonymous
wow you are such a genius. I admire you all
anonymous
  • anonymous
?
anonymous
  • anonymous
bt i need the radial accn, not the total accn....
anonymous
  • anonymous
at time t=0
anonymous
  • anonymous
yeh i dnt have clue on that :|
anonymous
  • anonymous
radial is apparently equal to centripetal= v^2 / r
anonymous
  • anonymous
but i dont have a clue
anonymous
  • anonymous
hey i got it neway ..thnx
nikvist
  • nikvist
\[\vec{a}_n=<-kt\sin{t},kt\cos{t}>\]
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