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anonymous
 5 years ago
A particle moves under a hypothetical force so that its velocity vector is v= <ktcost, ktsint>. Find its radial acceleration...Please help...
anonymous
 5 years ago
A particle moves under a hypothetical force so that its velocity vector is v= <ktcost, ktsint>. Find its radial acceleration...Please help...

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0whata hard bout that?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0acceleration is the derivative of velocity with respect to time

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0assuming k is a constant

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[a = < k \frac{d}{dt} ( tcos(t)) , k \frac{d}{dt} ( tsin(t) ) > \]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0k can be factored out of the vector, and it will just provide a scalar multiple

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[a = k < ( \cos(t) tsin(t)) , (\sin(t) + tcos(t)) > \]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0wow you are such a genius. I admire you all

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0bt i need the radial accn, not the total accn....

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yeh i dnt have clue on that :

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0radial is apparently equal to centripetal= v^2 / r

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0but i dont have a clue

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0hey i got it neway ..thnx

nikvist
 5 years ago
Best ResponseYou've already chosen the best response.1\[\vec{a}_n=<kt\sin{t},kt\cos{t}>\]
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