use de moivre's formula with n= 2 to find trigonometric identities cos2theta and sin 2theta plz help me.....:(

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use de moivre's formula with n= 2 to find trigonometric identities cos2theta and sin 2theta plz help me.....:(

Mathematics
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farily simple
fairly lol
\[(\cos(\theta) + isin(\theta))^n = cos(n \theta) +isin(n \theta ) ) \]

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\(\cos (2\theta)_1\sin(2\theta)=(\cos \theta +i \sin \theta)^2=(\cos^2\theta-sin^2\theta)+i(2\sin\theta\cos\theta)\)
^ that yeh :|
The left most expression should be \(\cos(2\theta)+i\sin(2\theta)\)
there is actually something to do here yes? besides using laws of exponents i mean.
oops my apologies whatchmath wrote it. should should also mumble something about setting real part = real part and imaginary part = imaginary part.
watchmath i mean. yikes it is early
Are you in US too satellite?
yes US
trying to learn latex and practicing here as much as i can

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