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Asadkarim7
 5 years ago
the tangent and normal to the curve y= sin x at the point P where x= π/3 cut the xaxis at A and B respectively
(a). show that AB = (5√3)/4.
(b). find the area of the triangle PAB.
Asadkarim7
 5 years ago
the tangent and normal to the curve y= sin x at the point P where x= π/3 cut the xaxis at A and B respectively (a). show that AB = (5√3)/4. (b). find the area of the triangle PAB.

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amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0the tangent to the curve is what..cos(pi/3) right?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0the normal is 90 from that....

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0i dont quite understand the cuts the x axis at A and B

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0maybe x and y axis at A and B?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0they mean the tangent cuts at a, and the normal cuts at b

Asadkarim7
 5 years ago
Best ResponseYou've already chosen the best response.2let me post the digaram

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0its very simple find the eqns of the lines , find the intercepts of those lines , then use distance formula

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0lol.... yeah, if you post it that would be more helpful :)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0simple yes, once you understand the question ;)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0just distance formula and area of a triangle = (1/2) bh , thats all there is , you dont even need a picture for this, should be able to draw one yourself, or visualise in your mind pretty easily

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0well the tangent is simply its derivative; cos(pi/3)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0the equation of the line then becomes: y(sin(pi/3)) = cos(pi/3)(x(pi/3))

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0cos(pi/3) = 1/2 right?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0the normal will have a slope of 2 then

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0y(sin(pi/3)) = 2(x(pi/3)) for the normal equation

Asadkarim7
 5 years ago
Best ResponseYou've already chosen the best response.2Guys i still cant understand it , can sun1 explain it to me step by step ? plz

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0they give you a point (pi/3, sin(pi/3)); or rather (pi/3, sqrt(3)/2) right?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0first take the derivative of sine, which is cosine. then plug in \[\frac{\pi}{3}\] into the derivative to get the slope. \[cos(\frac{\pi}{3})=\frac{1}{2}\] so that is the slope of the tangent line

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0at this level you should have some redimentary skills at a graph id assume :)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0use the poitslope form of a line to get the euation for the tangent and the norml

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0amistre is in right direction,find the eqn of tangent and normal to the curve, find the x intercepts of both to find out the coordiantes of the two points, point P is given, it forms the triangle ABP

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0someones been rearragnging my keyboard lol

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0the equation of the line use the point slope formula. the point is \[(\frac{\pi}{3},\frac{\sqrt{3}}{2})\] and the slope is \[\frac{1}{2}\] so the equation is \[y\frac{\sqrt{3}}{2}=\frac{1}{2}(x\frac{\pi}{3})\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0this crosses the x axis where \[y=0\] so set \[y=0\] and solve to get \[x=\frac{\pi}{3}\sqrt{3}\] if i did the algebra right

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0repeat the process for the line with slope 2 through \[(\frac{\pi}{3},\frac{\sqrt{3}}{2})\]

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0x/2  pi/6 = sqrt.3/2 x = sqrt3 + pi/3 its good ;)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0amistre did i screw this up? it looks good to me

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0the normal just uses 2 for th eslope then

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[y\frac{\sqrt{3}}{2}=2(x\frac{\pi}{3})\] is the normal line yes?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0let \[y=0\] get \[x=\sqrt{3}+\frac{\pi}{3}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0at least that is what i got

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0/ 2 to begin with to ease the process

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0sqrt.3/4 + pi/3 i think

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[\frac{\sqrt{3}}{2}=2(x\frac{\pi}{3})\] \[\sqrt{3}=x\frac{\pi}{3}\] \[x=\sqrt{3}+\frac{\pi}{3}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0whoooooooooooooooooops

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[\frac{\sqrt{3}}{4}+\frac{\pi}{3}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0another dumb guy award for me.

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0lol.... thats what all my medals are for ;)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok fine. now that we have the xintercepts, after some elementary algebra mistakes on my part, what are we supposed to do with them?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0throw tham at moving trains :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0u both deserve for it :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i forgot what we were supposed to do with these. multiply? add? find the length?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i mean for medals ;)..not throwing at the moving train :P

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0the distance between them is just large  small

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0now the final task, area of the triangle

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0since they are on the number line; distance between them is large  small

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0distance between 6 and 3 is 63 = 9 ;)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0height = sqrt3/2 ; distance = ls  = area 2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0meant to find an area lol but you guys have done it all over the place and its highly likely that the OP has just giving up on trying to follow what you guys have wrote

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0the journey taken is more important the the final destination....... grasshopper

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0sats been consistently and systematically finding the points... its good

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ooh some arithmetic i can do! \[\frac{\sqrt{3}}{4}+\frac{\pi}{3}(\frac{\pi}{3}\sqrt{3})=\frac{\sqrt{3}}{4}+\sqrt{3}=\frac{5\sqrt{3}}{4}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0wow just what it said it was!

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0very east to set out working out to make the solution of these questions look really easy instead of making it look so complicated with 1000s of posts etc.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0true but very hard to type all in in one box. specially if typesetting.

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0depends on if you wanna read a novel or have a conversation type environment; there isnt only one way to do things :)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0this type of environment is suited best for interaction between questioneer and answeer

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0if they really want a static read thru answer; theres always the internet lol

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Asadkarim7 i will be happy to work all this out on one paper and send it to you if this is confusing. the idea is this: find the slope of the tangent line, then find its equation. find the slope of the normal line, and its equation. then in each equation set y = 0 and solve for x. that is the whole idea. once you have both x intercepts subtract to get the distance. the rest is mechanics, but i will be happy to write it out in all its gory details without my algebra errors if you like

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0asad is intelligent :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i am sure he is but i will be happy to do it to practice my latex

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0:) latex.... i perfer ascii lol

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0^ "its very simple find the eqns of the lines , find the intercepts of those lines , then use distance formula" esessentially what I wrote like a whole hour ago

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0ohhh..... so everything after that is useless and should be erased becasue its just utter garbage? .... comes across a bit pompuos dontcha think ;)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0in fact the "i still dont understand can you explain it to me step by step" kinda leads me to believe otherwise ... lol

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0also, geez, way to spam the question guys, nw my computer is going extremely slow when I view this particular question because you guys spammed it so much :

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0youre prolly using internet explorer; i had to down firefox to avoid that

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0the equation editor stuff tends to put a strain on the processor; which is why i tend to avoid it

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0so asad; how can we help you with this problem?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0let me know if you have any questions

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0you forgot to put in the area lol

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0and here my fine useless garbage contribution ;)

Asadkarim7
 5 years ago
Best ResponseYou've already chosen the best response.2sattelite73 u made the equation y = sqrt 3/ 2 it should have been y sqrt 3/2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[\frac{1}{2}bh=\frac{1}{2}\times \frac{5\sqrt{3}}{4}\times \frac{\sqrt{3}}{2}=\frac{15}{16}\]

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0its his latex.... makes him go a little insane at times and starts putting = signs for  signs :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0everyone is a critic. ok that was a typo and look, it is gone!

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0that ones just blank.....

Asadkarim7
 5 years ago
Best ResponseYou've already chosen the best response.2u r genius sattelite 73

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0what lovely font! what nice equations!

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0how didi u make pdf file

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0eventually i will learn this latex ... eventually.

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0he starts out with some fine kindling, then adds a bit of tinder to feed the flame..

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i am using texmaker as an editor. just converts for you if you ask, and then can ask for external viewer. really quite friendly. i tried to use this on micordemon windows whatever and it took me maybe a day and a half to download what i needed. miktex and all that garbage. never worked right. left the darkside for linux a few months ago, to maybe 2 minutes do download and works like a charm.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0it is true i start with the trees. used to roll my own when i smoked. also doing html by hand if i can (with editor of course)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0<html> <body> <input type=button value="Click me!!" onClick="qwe()"> </body> <script language=javascript> function qwe() {alert("Quit it!")} </script> </html>

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0also spelled "point" and 'derivative' wrong. perils of not using wysiwyg

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0armistre will this make my computer explode?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0this will keep me busy for at least an hour. click, click, ...

Asadkarim7
 5 years ago
Best ResponseYou've already chosen the best response.2Thanks Everyone for your contributions , and giving your precious time to my question <3

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0i made a 'flip book' javascript movie maker for my neices

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0youre welcome :) and thank you elec for making it all possible lol

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0welcome. hope it is clear enough even with all this garbage thrown in.

Asadkarim7
 5 years ago
Best ResponseYou've already chosen the best response.2yeahh satellite its crystal clear . :)
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