determine the vertex (both coordinates). (-x^2/3)-(x/2)-(1/5)

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determine the vertex (both coordinates). (-x^2/3)-(x/2)-(1/5)

Mathematics
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1/2 ---- = -3/4 is your x coord i believe -2/3
-0.0125 = -1/8 would be the y coord.... if i see it right
(-1/3)x^2 -(1/2)x -(1/5) -2/3x -1/2 x = -1/2//2/3 = -3/4 ....yep

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Other answers:

2.5 4.25 8.125 16.0625
-5/16 maybe
125/1000 lol
\[\frac{-b}{2a}=\frac{\frac{1}{2}}{2\times -\frac{1}{3}}=-\frac{3}{4}\]\]
gonna have to ask a brit
(-.75,-.0125) ;)
i got -.95
(-((-.75)^2)) / 3) - ((-.75) / 2) - (1 / 5) = -0.0125 hot of the google
\[-2\times (-\frac{3}{4})^2-\frac{1}{2}\times -\frac{3}{4}-\frac{1}{5}\]
-2?
you are right. i was multiplying the first term by -2 because i am not paying attention.
it helps to sit facing a wall; that way when the butterflys float by you dont get distracted lol
just came to see if you were still here. you are more obsessed than i am!
thanks guys
im stiil trying to figure out you plug in -3/4 for x right?
yes, x = -3/4 = -.75
and how is y?
you simply use the value for x in the equation to determine what 'y' equals.... no easy way around htat

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