anonymous
  • anonymous
If a cup of tea has an initial temperature of 203 degree F in a room whose temperature is 70 degreeF, then according to Newton's law of cooling the temperature of the tea after t minute have passed is
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
T (t) =70+133e^(-t/5) what is the average temperature of the tea one hour after the initial time?? please help!
anonymous
  • anonymous
replace t by 1. \[T(1)=70+133e^{\frac{-1}{5}}\]
anonymous
  • anonymous
i get 178.89 to two decimal places

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amistre64
  • amistre64
should 133 be 203?
anonymous
  • anonymous
no
amistre64
  • amistre64
i see it now lol 203 - 70 right?
anonymous
  • anonymous
the room temp is 70, 203-70=133 and it is the difference that decays
anonymous
  • anonymous
how do you get that answer of 178.89 from that equation? b/c i got something different :(
amistre64
  • amistre64
yeah, so t = -60 minutes if that is accurate....
amistre64
  • amistre64
70 + (133 * (e^((-60) / 5))) = 70.0008172 is what google figures out
amistre64
  • amistre64
or is this a recursion equation.... and not a particular solution?
amistre64
  • amistre64
nah; particular it is; no place for a T{n-1} lol

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