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anonymous

  • 5 years ago

A spring in, when not taut, has length 10cm. suppose it takes 1kg m/sec^2 to compress the spring 1cm. What is the work required to stretch the spring 3cm?

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  1. amistre64
    • 5 years ago
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    W = F*d ; We integrate this somehow, gonna have to refresh meself on it tho

  2. amistre64
    • 5 years ago
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    {S} f(x) dx where f(x) = hookes law; kx

  3. amistre64
    • 5 years ago
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    k = 1kg and x = 1 cm; so ....still reading up on it lol

  4. amistre64
    • 5 years ago
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    oy its been awhile ..... 1000 kg m/sec^2 = k(.01m) maybe?

  5. amistre64
    • 5 years ago
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    k = 100 kg/sec^2 then i think

  6. amistre64
    • 5 years ago
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    the int this 100x (kg m/sec^2) from 0 to .03 m

  7. amistre64
    • 5 years ago
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    100x^2 ------- = 50x^2 at x=.03 2 50*.0009 = .045 maybe... I aint got the textbook with me to be sure :)

  8. anonymous
    • 5 years ago
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    i will make sure to double check with the t/b thanks amistre64 you are a big help! :)

  9. amistre64
    • 5 years ago
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    youre welcome :) it sounds right, but I just cant be sure ...its been to long since I tried doing spring calculus lol

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