anonymous
  • anonymous
how do i find the vertex of a function?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
If it's a parabola of the form \[ax ^{2} + bx + c \] then the vertex is given by -b/2a
anonymous
  • anonymous
You don't find the vertex of a function, per se, you find the vertex of something, like a parabola, an ellipse, etc.
myininaya
  • myininaya
not all parabolas are functions ellipses aren't functions unless you have the left and right raduis is 0 and the up and down radius is 0 then its just a dot and so it is a function

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anonymous
  • anonymous
my problem is find the vertex of f(x)=2x^2 it says find and label the vertex and the line of symmetry. do i have to graph it first?
myininaya
  • myininaya
f(x)=2(x-0)^2+0 vertex is (0,0)
myininaya
  • myininaya
i dont know how to find the lines of symmetry
anonymous
  • anonymous
but how do you know that? is it because there is no y intercept?
myininaya
  • myininaya
i put the parabola in vertex form f(x)=a(x-h)^2+k where (h,k) is the vertex
anonymous
  • anonymous
okay thanks. i got the symmetry part.
myininaya
  • myininaya
can you tell how you get symmetry part?
myininaya
  • myininaya
can we just since it is even it symmetric about x=0 or the y-axis
anonymous
  • anonymous
yes. its where ever the parabola can be split in half. theres a formula but i cant think of it off the top of my head so i just look at a graph and sometimes there is no line of symmetry
myininaya
  • myininaya
ok thanks nikki :) i put look for the formula later
anonymous
  • anonymous
Symmetry is related to the odd, even function business. An f(-x)=f(x) symmetric about the y axis. f(-x)=-f(x) symmetric about the origin.

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