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toxicsugar22

  • 5 years ago

(x-4)^2/9-(y+2)^2/16=1 give the exact coordinates of any four points on the hyperbola. and show me how you get this

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  1. anonymous
    • 5 years ago
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    wouldn't you just plug in any x or y number and factor to get the corresponding x or y value?

  2. anonymous
    • 5 years ago
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    First, try setting x=0, then y=0, these should be the easiest 2 points to get

  3. anonymous
    • 5 years ago
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    agreed

  4. toxicsugar22
    • 5 years ago
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    yes but can u help me further i tried

  5. toxicsugar22
    • 5 years ago
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    hi can u help me

  6. anonymous
    • 5 years ago
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    do you have a mac?

  7. anonymous
    • 5 years ago
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    if so, open grapher and plot the equation, this will let you see the curve.

  8. anonymous
    • 5 years ago
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    here is the algebra for x=0 \[16/9 - (y+2)^{2}/16 = 1\] \[5/9 = (y+2)^{2}/16\] \[40/9 = (y+2)^{2}\] \[y = -2+ (\sqrt{40})/3\]

  9. anonymous
    • 5 years ago
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    so that coordinate would be \[(0, -2+(\sqrt{40})/ 3)\]

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