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anonymous
 5 years ago
Assume that a sample is used to estimate a population mean mu. Use the given confidence level and sample data to find the margin of error. Assume that the sample is a simple random sample and the population has a normal distribution. Round your answer to one more decimal place than the sample standard deviation.
95% confidence; n = 21; xbar = 0.16; s = 0.16
anonymous
 5 years ago
Assume that a sample is used to estimate a population mean mu. Use the given confidence level and sample data to find the margin of error. Assume that the sample is a simple random sample and the population has a normal distribution. Round your answer to one more decimal place than the sample standard deviation. 95% confidence; n = 21; xbar = 0.16; s = 0.16

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[E=(1.96(0.16))/\sqrt{21}\] = 0.068

toxicsugar22
 5 years ago
Best ResponseYou've already chosen the best response.0hey meth.party can u help me after her

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I may have done this wrong, Are you looking for the margin of error of the mean or that of the proportion?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0The error of what exactly?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0of population mean mu

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0If thats what is sought then what I did above should be correct. What course is this?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0statistics thank you for all of your help so far

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0how about this one... Find the minimum sample size. You want to be 95% confident that the sample variance is within 20% of the population variance.
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