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anonymous

  • 5 years ago

Assume that a sample is used to estimate a population mean mu. Use the given confidence level and sample data to find the margin of error. Assume that the sample is a simple random sample and the population has a normal distribution. Round your answer to one more decimal place than the sample standard deviation. 95% confidence; n = 21; x-bar = 0.16; s = 0.16

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  1. anonymous
    • 5 years ago
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    \[E=(1.96(0.16))/\sqrt{21}\] = 0.068

  2. toxicsugar22
    • 5 years ago
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    hey meth.party can u help me after her

  3. anonymous
    • 5 years ago
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    I may have done this wrong, Are you looking for the margin of error of the mean or that of the proportion?

  4. anonymous
    • 5 years ago
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    margin of error

  5. anonymous
    • 5 years ago
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    The error of what exactly?

  6. anonymous
    • 5 years ago
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    of population mean mu

  7. anonymous
    • 5 years ago
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    If thats what is sought then what I did above should be correct. What course is this?

  8. anonymous
    • 5 years ago
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    statistics thank you for all of your help so far

  9. anonymous
    • 5 years ago
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    No problem!

  10. anonymous
    • 5 years ago
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    how about this one... Find the minimum sample size. You want to be 95% confident that the sample variance is within 20% of the population variance.

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