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anonymous

  • 5 years ago

6b^3-24b^2/b^2+b-20

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  1. anonymous
    • 5 years ago
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    You factor first then cancel out to get the answer.

  2. anonymous
    • 5 years ago
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    \[\frac{6b ^{3}-24b ^{2}}{b ^{2}+b-20} ?\]

  3. anonymous
    • 5 years ago
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    yes factor and cancel

  4. anonymous
    • 5 years ago
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    what's the answer

  5. anonymous
    • 5 years ago
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    u need answer?

  6. anonymous
    • 5 years ago
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    ok

  7. anonymous
    • 5 years ago
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    yes i need answer

  8. toxicsugar22
    • 5 years ago
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    hey can any1 help me after her

  9. anonymous
    • 5 years ago
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    show work too please

  10. anonymous
    • 5 years ago
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    6b^2/(b+5)

  11. anonymous
    • 5 years ago
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    \[\frac{6b ^{2}(b-4)}{(b+5)(b-4)}\] b-4 cancel \[\frac{6b ^{2}}{x+5}\]

  12. anonymous
    • 5 years ago
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    thank you! could you possibly help me with 2 more of these problems?

  13. anonymous
    • 5 years ago
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    If I deserve medal then give me one

  14. anonymous
    • 5 years ago
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    I will try the best

  15. anonymous
    • 5 years ago
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    i will give you 3 medals

  16. anonymous
    • 5 years ago
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    great

  17. anonymous
    • 5 years ago
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    just help me with 2 more of these type of problems

  18. anonymous
    • 5 years ago
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    post it

  19. anonymous
    • 5 years ago
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    b^2+4b-21/2b^2-18

  20. anonymous
    • 5 years ago
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    show all work too

  21. anonymous
    • 5 years ago
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    ok

  22. anonymous
    • 5 years ago
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    r u still there?

  23. anonymous
    • 5 years ago
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    \[\frac{b^{2}+4b-18}{2b ^{2}-18} = \frac{b ^{2}+4b-18}{2(b-3)(b+3}\]

  24. anonymous
    • 5 years ago
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    next

  25. anonymous
    • 5 years ago
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    ok tell me how to give you these medals

  26. anonymous
    • 5 years ago
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    next to my name click give medal or good answer

  27. anonymous
    • 5 years ago
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    any more question?

  28. anonymous
    • 5 years ago
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    you didnt factor it completely

  29. anonymous
    • 5 years ago
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    for the second one i asked you

  30. anonymous
    • 5 years ago
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    and after the second one, i have one more question to ask

  31. anonymous
    • 5 years ago
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    OK

  32. anonymous
    • 5 years ago
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    b^2 + 4b - 18.....You still needed to factor that one

  33. anonymous
    • 5 years ago
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    I will give you 5 medals actually, just give me the answer for this one and then i have 1 more

  34. anonymous
    • 5 years ago
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    a=1 b=4 c=-18 \[\frac{-b \pm \sqrt{b ^{2}-(4 \times a \times c)}}{2 \times a}\] can u solve?

  35. toxicsugar22
    • 5 years ago
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    hi can anyone help me after her

  36. anonymous
    • 5 years ago
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    next question is: 3b^2+15b/2b^3-50b...factor numerator then denominator, then cancel to get the answer.

  37. anonymous
    • 5 years ago
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    ill give out free medals just get me the answer quick. and show the work lol

  38. anonymous
    • 5 years ago
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    3b^2+15b/2b^3-50b

  39. anonymous
    • 5 years ago
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    r u still there?

  40. anonymous
    • 5 years ago
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    \[-4 \pm \sqrt{22}\]\[\frac{-4\pm \sqrt{4^{2}-(4\times 1 \times _-18)}}{2 \times 1}\]\[\frac{-4\pm \sqrt{16+72}}{2}= \frac{-4\pm \sqrt{88} }{2}\] \[\frac{-4\pm 2\sqrt{22}}{2}\] yes , my computer go slow ' I 'm mad ,doesn't let me go fast

  41. anonymous
    • 5 years ago
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    what does the answer simplify to?

  42. anonymous
    • 5 years ago
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    my computer weir \[-2\pm \sqrt{22}\]

  43. anonymous
    • 5 years ago
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    thats not the answer though because i have a list of answers and this one is not there

  44. anonymous
    • 5 years ago
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    u probly solving it wrong or too much

  45. anonymous
    • 5 years ago
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    i need refesh my computer ,i will back with correct answer

  46. anonymous
    • 5 years ago
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    i need refesh my computer ,i will back with correct answer

  47. anonymous
    • 5 years ago
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    i need refesh my computer ,i will back with correct answer

  48. anonymous
    • 5 years ago
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    ok

  49. anonymous
    • 5 years ago
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    b^2 + 4b - 18\[-2\pm \sqrt{22}\] this correct answer, I did check ' 3b^2+15b/2b^3-50b \[\frac{3b(b+5)}{2b(b+5)(b-5)}\] (b+5) b cancel \[\frac{3}{2(b-5)}\]

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