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anonymous

  • 5 years ago

3x^2-5x-13=0

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  1. anonymous
    • 5 years ago
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    Do you have any specific method? remember it can be solved by factoring, or by the general cuadratic formula..

  2. anonymous
    • 5 years ago
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    no

  3. anonymous
    • 5 years ago
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    give me one minute

  4. anonymous
    • 5 years ago
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    okay. thank you for your help.

  5. anonymous
    • 5 years ago
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    a = 3; b = -5; c = -13 because the discriminant (b^2 - 4 ac = -13) is negative, this equation has not a real solution. Thus, applying the general formula for quadratic equation, we get : x1=\[1/6(5+i*\sqrt{181})\] x2=\[1/6(5-i*\sqrt{181})\]

  6. anonymous
    • 5 years ago
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    Wait. Ther is a mistake. The discriminant is positive. Gonna fix it

  7. anonymous
    • 5 years ago
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    okay. thank you so much.

  8. toxicsugar22
    • 5 years ago
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    hi emmunrrad can u help me after her

  9. anonymous
    • 5 years ago
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    sure

  10. toxicsugar22
    • 5 years ago
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    thanks

  11. anonymous
    • 5 years ago
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    Check the attachment

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  12. anonymous
    • 5 years ago
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    The solution is in the attachment

  13. anonymous
    • 5 years ago
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    is that what you want?

  14. anonymous
    • 5 years ago
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    Because discriminant is positive, you have two solutions for you equation; they are: x1 = 3.075604007845618 x2 = -1.40893734117895

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