anonymous
  • anonymous
3x^2-5x-13=0
Mathematics
jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
Do you have any specific method? remember it can be solved by factoring, or by the general cuadratic formula..
anonymous
  • anonymous
no
anonymous
  • anonymous
give me one minute

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anonymous
  • anonymous
okay. thank you for your help.
anonymous
  • anonymous
a = 3; b = -5; c = -13 because the discriminant (b^2 - 4 ac = -13) is negative, this equation has not a real solution. Thus, applying the general formula for quadratic equation, we get : x1=\[1/6(5+i*\sqrt{181})\] x2=\[1/6(5-i*\sqrt{181})\]
anonymous
  • anonymous
Wait. Ther is a mistake. The discriminant is positive. Gonna fix it
anonymous
  • anonymous
okay. thank you so much.
toxicsugar22
  • toxicsugar22
hi emmunrrad can u help me after her
anonymous
  • anonymous
sure
toxicsugar22
  • toxicsugar22
thanks
anonymous
  • anonymous
Check the attachment
1 Attachment
anonymous
  • anonymous
The solution is in the attachment
anonymous
  • anonymous
is that what you want?
anonymous
  • anonymous
Because discriminant is positive, you have two solutions for you equation; they are: x1 = 3.075604007845618 x2 = -1.40893734117895

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