anonymous 5 years ago 3x^2-5x-13=0

1. anonymous

Do you have any specific method? remember it can be solved by factoring, or by the general cuadratic formula..

2. anonymous

no

3. anonymous

give me one minute

4. anonymous

okay. thank you for your help.

5. anonymous

a = 3; b = -5; c = -13 because the discriminant (b^2 - 4 ac = -13) is negative, this equation has not a real solution. Thus, applying the general formula for quadratic equation, we get : x1=$1/6(5+i*\sqrt{181})$ x2=$1/6(5-i*\sqrt{181})$

6. anonymous

Wait. Ther is a mistake. The discriminant is positive. Gonna fix it

7. anonymous

okay. thank you so much.

8. toxicsugar22

hi emmunrrad can u help me after her

9. anonymous

sure

10. toxicsugar22

thanks

11. anonymous

Check the attachment

12. anonymous

The solution is in the attachment

13. anonymous

is that what you want?

14. anonymous

Because discriminant is positive, you have two solutions for you equation; they are: x1 = 3.075604007845618 x2 = -1.40893734117895