anonymous
  • anonymous
how do you graph this system of equations x-y=3 x-2y=3
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
Easy you first find what y and x equal by using elimination
anonymous
  • anonymous
Do you know how to do elimination? (:
anonymous
  • anonymous
yes, i think..

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anonymous
  • anonymous
You need me to clarify? (:
anonymous
  • anonymous
please?
anonymous
  • anonymous
Haha yea sure (: Okay so you have to firsy see if anything can cancel out
anonymous
  • anonymous
first*
anonymous
  • anonymous
As you can see nothing cancels out. Since your graphing it wont matter which one you start with. So then you have to think what do i have to multiply so that either the x or y variables will be crossed out
anonymous
  • anonymous
I would try to cross the Y variable out first. So you Have to Multiply the whole equation (x - y = 3) by 2 so that the y will cross out so then
anonymous
  • anonymous
I take that back you would multiply by -2
anonymous
  • anonymous
So that you would be able to cross them out ( negative & positive)
anonymous
  • anonymous
Okay so then you would get 2x + 2y = 6
anonymous
  • anonymous
If you set them up like so 2x + 2y = 6 x - 2y = 3 You would see that the 2y does no indeed, cancel out. So then you'd get
anonymous
  • anonymous
does* not does not lol
anonymous
  • anonymous
So then if you add the two equations you get 3x = 9 x = 3 Then to solve for Y You would have
anonymous
  • anonymous
\[\text{Psst, 'graph' $\not=$ 'solve'} \]
anonymous
  • anonymous
Haha i know. But this is also a good way to do it. Okay so then you would plug the 3 in for x
anonymous
  • anonymous
-3?
anonymous
  • anonymous
No offence, but this is a very long way to do it.
anonymous
  • anonymous
Its the way i was taught....
anonymous
  • anonymous
Why dont YOU help him then :P
anonymous
  • anonymous
i really appreciate the help
anonymous
  • anonymous
lol
anonymous
  • anonymous
is y= -3?
anonymous
  • anonymous
Yes, im pretty sure (: Go ahead and show me how you got that and i will tell you if its correct. Btw sorry Newton I just have an immense respect for my teachers ^_^ Even though most the time I dont like them
anonymous
  • anonymous
you put 3 in for x in one of the equations?
anonymous
  • anonymous
Your teachers taught you that is how to figure out how to graph an equation?
anonymous
  • anonymous
No they taught me to find the variables and then graph... lol easy peasy..
anonymous
  • anonymous
The steps just seem long, after you did it a lot its not that hard :P
anonymous
  • anonymous
do*
toxicsugar22
  • toxicsugar22
hi can anyone here help me after u help her
anonymous
  • anonymous
Yes dark lol.. (: Okay and then you do y-intercept and slope to graph (:
anonymous
  • anonymous
\[x-y = 3 \implies y = x-3 \] \[x-2y = 3 \implies y = \frac{x-3}{2} \] You (should be able to!) can graph these right form here, as they are in the form y = mx + c. But setting x = 0, y = 0 to find the intercepts may help.
anonymous
  • anonymous
im a guy* thnak you! lol
anonymous
  • anonymous
x - slope and y = y intercept
anonymous
  • anonymous
Ik your a guy.. haha
toxicsugar22
  • toxicsugar22
oh srry can someone help me after him
anonymous
  • anonymous
toxicsugar said her*........ anyways.................thank you very much!
anonymous
  • anonymous
Haha oh.. ^_^ blonde moment... And yes good process. That's just the way i was taught ^_^

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