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anonymous
 5 years ago
how do you graph this system of equations
xy=3
x2y=3
anonymous
 5 years ago
how do you graph this system of equations xy=3 x2y=3

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Easy you first find what y and x equal by using elimination

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Do you know how to do elimination? (:

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0You need me to clarify? (:

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Haha yea sure (: Okay so you have to firsy see if anything can cancel out

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0As you can see nothing cancels out. Since your graphing it wont matter which one you start with. So then you have to think what do i have to multiply so that either the x or y variables will be crossed out

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I would try to cross the Y variable out first. So you Have to Multiply the whole equation (x  y = 3) by 2 so that the y will cross out so then

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I take that back you would multiply by 2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0So that you would be able to cross them out ( negative & positive)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Okay so then you would get 2x + 2y = 6

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0If you set them up like so 2x + 2y = 6 x  2y = 3 You would see that the 2y does no indeed, cancel out. So then you'd get

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0does* not does not lol

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0So then if you add the two equations you get 3x = 9 x = 3 Then to solve for Y You would have

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[\text{Psst, 'graph' $\not=$ 'solve'} \]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Haha i know. But this is also a good way to do it. Okay so then you would plug the 3 in for x

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0No offence, but this is a very long way to do it.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Its the way i was taught....

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Why dont YOU help him then :P

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i really appreciate the help

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Yes, im pretty sure (: Go ahead and show me how you got that and i will tell you if its correct. Btw sorry Newton I just have an immense respect for my teachers ^_^ Even though most the time I dont like them

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0you put 3 in for x in one of the equations?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Your teachers taught you that is how to figure out how to graph an equation?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0No they taught me to find the variables and then graph... lol easy peasy..

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0The steps just seem long, after you did it a lot its not that hard :P

toxicsugar22
 5 years ago
Best ResponseYou've already chosen the best response.0hi can anyone here help me after u help her

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Yes dark lol.. (: Okay and then you do yintercept and slope to graph (:

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[xy = 3 \implies y = x3 \] \[x2y = 3 \implies y = \frac{x3}{2} \] You (should be able to!) can graph these right form here, as they are in the form y = mx + c. But setting x = 0, y = 0 to find the intercepts may help.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0im a guy* thnak you! lol

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0x  slope and y = y intercept

toxicsugar22
 5 years ago
Best ResponseYou've already chosen the best response.0oh srry can someone help me after him

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0toxicsugar said her*........ anyways.................thank you very much!

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Haha oh.. ^_^ blonde moment... And yes good process. That's just the way i was taught ^_^
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