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anonymous

  • 5 years ago

how do you graph this system of equations x-y=3 x-2y=3

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  1. anonymous
    • 5 years ago
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    Easy you first find what y and x equal by using elimination

  2. anonymous
    • 5 years ago
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    Do you know how to do elimination? (:

  3. anonymous
    • 5 years ago
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    yes, i think..

  4. anonymous
    • 5 years ago
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    You need me to clarify? (:

  5. anonymous
    • 5 years ago
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    please?

  6. anonymous
    • 5 years ago
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    Haha yea sure (: Okay so you have to firsy see if anything can cancel out

  7. anonymous
    • 5 years ago
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    first*

  8. anonymous
    • 5 years ago
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    As you can see nothing cancels out. Since your graphing it wont matter which one you start with. So then you have to think what do i have to multiply so that either the x or y variables will be crossed out

  9. anonymous
    • 5 years ago
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    I would try to cross the Y variable out first. So you Have to Multiply the whole equation (x - y = 3) by 2 so that the y will cross out so then

  10. anonymous
    • 5 years ago
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    I take that back you would multiply by -2

  11. anonymous
    • 5 years ago
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    So that you would be able to cross them out ( negative & positive)

  12. anonymous
    • 5 years ago
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    Okay so then you would get 2x + 2y = 6

  13. anonymous
    • 5 years ago
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    If you set them up like so 2x + 2y = 6 x - 2y = 3 You would see that the 2y does no indeed, cancel out. So then you'd get

  14. anonymous
    • 5 years ago
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    does* not does not lol

  15. anonymous
    • 5 years ago
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    So then if you add the two equations you get 3x = 9 x = 3 Then to solve for Y You would have

  16. anonymous
    • 5 years ago
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    \[\text{Psst, 'graph' $\not=$ 'solve'} \]

  17. anonymous
    • 5 years ago
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    Haha i know. But this is also a good way to do it. Okay so then you would plug the 3 in for x

  18. anonymous
    • 5 years ago
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    -3?

  19. anonymous
    • 5 years ago
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    No offence, but this is a very long way to do it.

  20. anonymous
    • 5 years ago
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    Its the way i was taught....

  21. anonymous
    • 5 years ago
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    Why dont YOU help him then :P

  22. anonymous
    • 5 years ago
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    i really appreciate the help

  23. anonymous
    • 5 years ago
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    lol

  24. anonymous
    • 5 years ago
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    is y= -3?

  25. anonymous
    • 5 years ago
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    Yes, im pretty sure (: Go ahead and show me how you got that and i will tell you if its correct. Btw sorry Newton I just have an immense respect for my teachers ^_^ Even though most the time I dont like them

  26. anonymous
    • 5 years ago
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    you put 3 in for x in one of the equations?

  27. anonymous
    • 5 years ago
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    Your teachers taught you that is how to figure out how to graph an equation?

  28. anonymous
    • 5 years ago
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    No they taught me to find the variables and then graph... lol easy peasy..

  29. anonymous
    • 5 years ago
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    The steps just seem long, after you did it a lot its not that hard :P

  30. anonymous
    • 5 years ago
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    do*

  31. toxicsugar22
    • 5 years ago
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    hi can anyone here help me after u help her

  32. anonymous
    • 5 years ago
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    Yes dark lol.. (: Okay and then you do y-intercept and slope to graph (:

  33. anonymous
    • 5 years ago
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    \[x-y = 3 \implies y = x-3 \] \[x-2y = 3 \implies y = \frac{x-3}{2} \] You (should be able to!) can graph these right form here, as they are in the form y = mx + c. But setting x = 0, y = 0 to find the intercepts may help.

  34. anonymous
    • 5 years ago
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    im a guy* thnak you! lol

  35. anonymous
    • 5 years ago
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    x - slope and y = y intercept

  36. anonymous
    • 5 years ago
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    Ik your a guy.. haha

  37. toxicsugar22
    • 5 years ago
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    oh srry can someone help me after him

  38. anonymous
    • 5 years ago
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    toxicsugar said her*........ anyways.................thank you very much!

  39. anonymous
    • 5 years ago
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    Haha oh.. ^_^ blonde moment... And yes good process. That's just the way i was taught ^_^

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