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anonymous

  • 5 years ago

how would you integrate (x^2 + 4)/x ?

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  1. anonymous
    • 5 years ago
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    \[(x ^{2} + 4)/x = x ^{2}/x + 4/x = x + 4/x \] This should make it more obvious.

  2. anonymous
    • 5 years ago
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    ... well then, haha. thanks. thinking WAY too much into it.

  3. anonymous
    • 5 years ago
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    You should get: \[x ^{2}/2 + 4\ln x + C \] as the answer.

  4. anonymous
    • 5 years ago
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    yup- that's what i got. how would i go about solving for x then if C = 1 and the equation = 0? i can't figure out how to find some kind of like term to get a u term alone on the left side

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