anonymous 5 years ago compute the derivative y' of y=xsinxcosx

1. watchmath

We can rewrite y as $$y=\frac{1}{2}x\sin(2x)$$ Hence $$y'=\frac{1}{2}\sin(2x)+x\cos(2x)$$

2. anonymous

u did the product rule when taking the derivative?

3. watchmath

yes

4. anonymous

when u write xcos2x? can u explain why

5. watchmath

$$y'=\frac{1}{2}\sin(2x)+\frac{1}{2}x\cdot 2\cos(2x)$$

6. anonymous

ok./.... thank u very much