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anonymous

  • 5 years ago

f(x)=x^4-3x^3+6x^2-2x-12 find real zeros

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  1. anonymous
    • 5 years ago
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    can you factor that expression?

  2. anonymous
    • 5 years ago
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    I've tried to... but I can't figure it out.

  3. anonymous
    • 5 years ago
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    Wolfram presents the following.

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  4. anonymous
    • 5 years ago
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    This makes me think there is not way to factor this. Wolfram is really good at factoring. Do you need the answer or spep by step procedure?

  5. anonymous
    • 5 years ago
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    x1 -> 1.15181 - 2.23019 i x2 -> 1.15181 + 2.23019 I x3 -> -1.07514 x4 -> 1.77152 this are the four solutions for that expresion

  6. anonymous
    • 5 years ago
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    Ok. Thanks.

  7. anonymous
    • 5 years ago
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    I tried factoring, but I cant figure it out either. Lets supposse there is not a way jaja

  8. anonymous
    • 5 years ago
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    there probably isnt. Thanks for trying though! :)

  9. anonymous
    • 5 years ago
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    np

  10. dumbcow
    • 5 years ago
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    emunrrad how did you get your solution? i took derivative and used newtons method and found x = -1,2 only 2 real solutions because no inflection points exist

  11. anonymous
    • 5 years ago
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    I used Mathematica from wolfram. Can you show us how to do that?

  12. dumbcow
    • 5 years ago
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    using these solutions you can use synthetic division to get factored form =(x+1)(x-2)(x^2-2x+6)

  13. anonymous
    • 5 years ago
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    I tried synthetic division. But I got stoke and didn't know how to continue and just assumed I was doing it wrong.

  14. dumbcow
    • 5 years ago
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    http://en.wikipedia.org/wiki/Newton%27s_method

  15. anonymous
    • 5 years ago
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    gonna check it out.

  16. dumbcow
    • 5 years ago
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    well to solve just by using synthetic division, there are many possibilities any factor of -12 could work you would have to try +-1,2,3,4,6,12 -1 and 2 should have worked for you

  17. dumbcow
    • 5 years ago
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    the other 2 complex solutions would be: 1+- sqrt(5)i from quadratic formula x^2-2x+6 =0

  18. anonymous
    • 5 years ago
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    That makes a bit more since now. Thank you.

  19. anonymous
    • 5 years ago
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    Yeah, I worked it out by synthetic divsion, -1 works, then 2 works. So (x+1)(x-2)(x^2-2x+6). I hadn't done synthetic division in a while so I brushed up on it in five minutes here http://www.purplemath.com/modules/synthdiv.htm

  20. dumbcow
    • 5 years ago
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    synthetic division is nice but its a lot of work for finding zeroes, especially when constant has many factors and what if none of them work, you are assuming it has integer zeroes

  21. anonymous
    • 5 years ago
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    For a pre-calculus course, synthetic division would be was is expected. The heavy armo, Newton's method is for higher math, I think brokenangel is working her way there.

  22. dumbcow
    • 5 years ago
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    oh sorry, yeah i agree i was just speaking in general thats true newton method is meaningless if you haven't had calculus :)

  23. anonymous
    • 5 years ago
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    haha nope. this is algebra 2 stuff for me.

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