anonymous
  • anonymous
f(x)=x^4-3x^3+6x^2-2x-12 find real zeros
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
can you factor that expression?
anonymous
  • anonymous
I've tried to... but I can't figure it out.
anonymous
  • anonymous
Wolfram presents the following.
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anonymous
  • anonymous
This makes me think there is not way to factor this. Wolfram is really good at factoring. Do you need the answer or spep by step procedure?
anonymous
  • anonymous
x1 -> 1.15181 - 2.23019 i x2 -> 1.15181 + 2.23019 I x3 -> -1.07514 x4 -> 1.77152 this are the four solutions for that expresion
anonymous
  • anonymous
Ok. Thanks.
anonymous
  • anonymous
I tried factoring, but I cant figure it out either. Lets supposse there is not a way jaja
anonymous
  • anonymous
there probably isnt. Thanks for trying though! :)
anonymous
  • anonymous
np
dumbcow
  • dumbcow
emunrrad how did you get your solution? i took derivative and used newtons method and found x = -1,2 only 2 real solutions because no inflection points exist
anonymous
  • anonymous
I used Mathematica from wolfram. Can you show us how to do that?
dumbcow
  • dumbcow
using these solutions you can use synthetic division to get factored form =(x+1)(x-2)(x^2-2x+6)
anonymous
  • anonymous
I tried synthetic division. But I got stoke and didn't know how to continue and just assumed I was doing it wrong.
dumbcow
  • dumbcow
http://en.wikipedia.org/wiki/Newton%27s_method
anonymous
  • anonymous
gonna check it out.
dumbcow
  • dumbcow
well to solve just by using synthetic division, there are many possibilities any factor of -12 could work you would have to try +-1,2,3,4,6,12 -1 and 2 should have worked for you
dumbcow
  • dumbcow
the other 2 complex solutions would be: 1+- sqrt(5)i from quadratic formula x^2-2x+6 =0
anonymous
  • anonymous
That makes a bit more since now. Thank you.
anonymous
  • anonymous
Yeah, I worked it out by synthetic divsion, -1 works, then 2 works. So (x+1)(x-2)(x^2-2x+6). I hadn't done synthetic division in a while so I brushed up on it in five minutes here http://www.purplemath.com/modules/synthdiv.htm
dumbcow
  • dumbcow
synthetic division is nice but its a lot of work for finding zeroes, especially when constant has many factors and what if none of them work, you are assuming it has integer zeroes
anonymous
  • anonymous
For a pre-calculus course, synthetic division would be was is expected. The heavy armo, Newton's method is for higher math, I think brokenangel is working her way there.
dumbcow
  • dumbcow
oh sorry, yeah i agree i was just speaking in general thats true newton method is meaningless if you haven't had calculus :)
anonymous
  • anonymous
haha nope. this is algebra 2 stuff for me.

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