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anonymous
 5 years ago
prove the statement true :
1^2 +4^2 + 7^2 + ..... + (3n2)^2 = [n (6n^2  3n 1)] / 2
anonymous
 5 years ago
prove the statement true : 1^2 +4^2 + 7^2 + ..... + (3n2)^2 = [n (6n^2  3n 1)] / 2

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Hint: Direct use of Induction

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0this is not true for n=2

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0are you sure u type this incorrectly?

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0nvm im wrong i forgot to 1 to the lhs so it does hold for n=2
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