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anonymous

  • 5 years ago

Can anyone help solve this crazy equation, please!? 20^3+20^2(20/3)-20(20/3)^2-(20/3)^3

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  1. anonymous
    • 5 years ago
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    \[20^{3}+20^{2}(20/3)-20(20/3)^{2}-(20/3)^{3}\]

  2. dumbcow
    • 5 years ago
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    i thought maybe it could be factored but i don't think so just use order of operations and use a calculator :)

  3. anonymous
    • 5 years ago
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    \[[27(8000)+9(8000)-3(8000)-(8000)]/27\]

  4. anonymous
    • 5 years ago
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    you can factor 20^3 out of everything

  5. anonymous
    • 5 years ago
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    [(8000)(27+9-3-1)]/27

  6. anonymous
    • 5 years ago
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    [(8000)(32)]/27

  7. dumbcow
    • 5 years ago
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    9481.48148

  8. anonymous
    • 5 years ago
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    256000/27

  9. anonymous
    • 5 years ago
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    9481.481481...................

  10. anonymous
    • 5 years ago
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    ok how aare you guys getting these values? where did the 27, 9,3 and 1 come from?

  11. anonymous
    • 5 years ago
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    27 is common denominator

  12. anonymous
    • 5 years ago
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    how?

  13. anonymous
    • 5 years ago
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    it looks like it's 3.

  14. anonymous
    • 5 years ago
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    20^3+20^2(20/3)-20(20/3)^2-(20/3)^3 1st term (20^3) = (20^3)/1 2nd term 20^2(20/3) = (20^3)/3 3rd term -20(20/3)^2 = -(20^3)/9 4th term -(20/3)^3 = -(20^3)/27 Now let (20/3) = x so you have (x/1) + (x/3) - (x/9) - (x/27) Hope it helps!

  15. anonymous
    • 5 years ago
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    Actually, your answer turned on the light bulb, so to speak! I do understand, of course it is very confusing to me, but I get the 27, now I just need to take notes from your post up there and apply it to my work here. Thanks so much! That was great! Don't know what I would have done without the help here!

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