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anonymous
 5 years ago
find a fourtdregree polynomial function passing through the point (1,16) with roots of 0,1(multiplicity 2), and 3, i am studying for a quiz
anonymous
 5 years ago
find a fourtdregree polynomial function passing through the point (1,16) with roots of 0,1(multiplicity 2), and 3, i am studying for a quiz

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0you know this problem?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0f(x) = a*x(x+3)(x1)^2 solve for a using given point 16 = a*(1)(1+3)(11)^2 solve for a

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0sorry, just means multiplying

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0where you get a and x anyway?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0a is like a scale factor, it determines how skinny or wide the graph is kind of like the slope

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so it should be x infrotn of (1) etc?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0no i was replacing x with 1 because the function passes through the point (1,16) where the x_value is 1

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0then 1(1) etc, ? i got confused with ax , but i get it the you replace it.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i understand what you have to do next, multy,

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ah ok lets say you have a parabola y = (x1)^2 it has one zero at x=1 right? but what about y = 5(x1)^2 it also has one zero at x=1, however its a different function, its a narrower parabola so given the zeroes we can put the function into factored form but we dont know how the graph looks thats where the a comes from. the point given allows us to solve for a thus giving us the entire function

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yes multiply and get a by itself

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yeah i see it, so is going to be , 16=1(etc?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok thx, going go to sleep, at what time you usually on dude?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0depends, usually at night im on pacific time

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yeah and definitely later too

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0hey, ok, you subtitude, then what?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0was stoke for awhile, while working on it

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0oh ok same one so you substituted the x,y values in from the point they gave you then you solve for a, get it by itself

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0what i got right now 16=a(1)(1+3)(11)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok use PEMDAS do the parenthesis first (11)^2 = (2)^2 = 4

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok now you got, 16=a(1)(4)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0what happened to the (1+3) ??

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yep good 16 = a(1)(8)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0we found a, now we must replace a with 2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0correct now use that and put it back in the equation

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0to what equipon. 16=2x(x+3)(x1)^2?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0the very first one now we put the x's and y's back in

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0f(x) = ax(x+3)(x1)^2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0just replace a with 2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0how you find the fourt root?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0woah not x, replace a with 2 thats what we just solved for

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0??? fourth root of what

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0you looking for the fourt root

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0no its a fourth degree polynomial it just means our function has a x^4 term

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok, how you start then?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i dont know what you mean you just did it answer is f(x) = 2x(x+3)(x1)^2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0but the question is, find the fourt root

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0is find the fourt dree polynomial function

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i thought all along,to find the fourt root

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0there are 3 real roots 0,3,1

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0no really, their is four, 1 has multicplicity of 2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok thank, yoiu being great help to me,good night
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