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anonymous

  • 5 years ago

find a fourt-dregree polynomial function passing through the point (-1,16) with roots of 0,1(multiplicity 2), and -3, i am studying for a quiz

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  1. anonymous
    • 5 years ago
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    you know this problem?

  2. dumbcow
    • 5 years ago
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    f(x) = a*x(x+3)(x-1)^2 solve for a using given point 16 = a*(-1)(-1+3)(-1-1)^2 solve for a

  3. anonymous
    • 5 years ago
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    wait, a*x?

  4. dumbcow
    • 5 years ago
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    sorry, just means multiplying

  5. anonymous
    • 5 years ago
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    a*x?

  6. anonymous
    • 5 years ago
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    where you get a and x anyway?

  7. dumbcow
    • 5 years ago
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    a is like a scale factor, it determines how skinny or wide the graph is kind of like the slope

  8. anonymous
    • 5 years ago
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    so it should be x infrotn of (-1) etc?

  9. dumbcow
    • 5 years ago
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    no i was replacing x with -1 because the function passes through the point (-1,16) where the x_value is -1

  10. anonymous
    • 5 years ago
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    then -1(-1) etc, ? i got confused with ax , but i get it the you replace it.

  11. anonymous
    • 5 years ago
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    i understand what you have to do next, multy,

  12. dumbcow
    • 5 years ago
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    ah ok lets say you have a parabola y = (x-1)^2 it has one zero at x=1 right? but what about y = 5(x-1)^2 it also has one zero at x=1, however its a different function, its a narrower parabola so given the zeroes we can put the function into factored form but we dont know how the graph looks thats where the a comes from. the point given allows us to solve for a thus giving us the entire function

  13. dumbcow
    • 5 years ago
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    yes multiply and get a by itself

  14. anonymous
    • 5 years ago
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    yeah i see it, so is going to be , 16=-1(etc?

  15. dumbcow
    • 5 years ago
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    yeah

  16. anonymous
    • 5 years ago
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    ok thx, going go to sleep, at what time you usually on dude?

  17. dumbcow
    • 5 years ago
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    depends, usually at night im on pacific time

  18. anonymous
    • 5 years ago
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    ok, so at this time?

  19. dumbcow
    • 5 years ago
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    yeah and definitely later too

  20. anonymous
    • 5 years ago
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    ok, bye

  21. anonymous
    • 5 years ago
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    hey, ok, you subtitude, then what?

  22. anonymous
    • 5 years ago
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    was stoke for awhile, while working on it

  23. dumbcow
    • 5 years ago
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    oh ok same one so you substituted the x,y values in from the point they gave you then you solve for a, get it by itself

  24. anonymous
    • 5 years ago
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    what i got right now 16=a(-1)(-1+3)(-1-1)

  25. dumbcow
    • 5 years ago
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    ok use PEMDAS do the parenthesis first (-1-1)^2 = (-2)^2 = 4

  26. anonymous
    • 5 years ago
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    ok now you got, 16=a(-1)(4)

  27. dumbcow
    • 5 years ago
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    what happened to the (-1+3) ??

  28. anonymous
    • 5 years ago
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    forogt..

  29. anonymous
    • 5 years ago
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    8

  30. dumbcow
    • 5 years ago
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    yep good 16 = a(-1)(8)

  31. anonymous
    • 5 years ago
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    16=-8a -2=a

  32. anonymous
    • 5 years ago
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    we found a, now we must replace a with -2

  33. dumbcow
    • 5 years ago
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    correct now use that and put it back in the equation

  34. anonymous
    • 5 years ago
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    to what equipon. 16=-2x(x+3)(x-1)^2?

  35. dumbcow
    • 5 years ago
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    the very first one now we put the x's and y's back in

  36. anonymous
    • 5 years ago
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    ?

  37. dumbcow
    • 5 years ago
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    f(x) = ax(x+3)(x-1)^2

  38. dumbcow
    • 5 years ago
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    just replace a with -2

  39. anonymous
    • 5 years ago
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    -2a(1)(9) -18a

  40. anonymous
    • 5 years ago
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    how you find the fourt root?

  41. dumbcow
    • 5 years ago
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    woah not x, replace a with -2 thats what we just solved for

  42. dumbcow
    • 5 years ago
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    ??? fourth root of what

  43. anonymous
    • 5 years ago
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    you looking for the fourt root

  44. dumbcow
    • 5 years ago
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    no its a fourth degree polynomial it just means our function has a x^4 term

  45. anonymous
    • 5 years ago
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    ok, how you start then?

  46. dumbcow
    • 5 years ago
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    i dont know what you mean you just did it answer is f(x) = -2x(x+3)(x-1)^2

  47. anonymous
    • 5 years ago
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    but the question is, find the fourt root

  48. anonymous
    • 5 years ago
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    oh NOT

  49. anonymous
    • 5 years ago
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    is find the fourt dree polynomial function

  50. anonymous
    • 5 years ago
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    i thought all along,to find the fourt root

  51. dumbcow
    • 5 years ago
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    there are 3 real roots 0,-3,1

  52. anonymous
    • 5 years ago
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    no really, their is four, 1 has multicplicity of 2

  53. dumbcow
    • 5 years ago
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    correct

  54. anonymous
    • 5 years ago
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    ok thank, yoiu being great help to me,good night

  55. dumbcow
    • 5 years ago
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    :)

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