find a fourt-dregree polynomial function passing through the point (-1,16) with roots of 0,1(multiplicity 2), and -3, i am studying for a quiz

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find a fourt-dregree polynomial function passing through the point (-1,16) with roots of 0,1(multiplicity 2), and -3, i am studying for a quiz

Mathematics
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you know this problem?
f(x) = a*x(x+3)(x-1)^2 solve for a using given point 16 = a*(-1)(-1+3)(-1-1)^2 solve for a
wait, a*x?

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Other answers:

sorry, just means multiplying
a*x?
where you get a and x anyway?
a is like a scale factor, it determines how skinny or wide the graph is kind of like the slope
so it should be x infrotn of (-1) etc?
no i was replacing x with -1 because the function passes through the point (-1,16) where the x_value is -1
then -1(-1) etc, ? i got confused with ax , but i get it the you replace it.
i understand what you have to do next, multy,
ah ok lets say you have a parabola y = (x-1)^2 it has one zero at x=1 right? but what about y = 5(x-1)^2 it also has one zero at x=1, however its a different function, its a narrower parabola so given the zeroes we can put the function into factored form but we dont know how the graph looks thats where the a comes from. the point given allows us to solve for a thus giving us the entire function
yes multiply and get a by itself
yeah i see it, so is going to be , 16=-1(etc?
yeah
ok thx, going go to sleep, at what time you usually on dude?
depends, usually at night im on pacific time
ok, so at this time?
yeah and definitely later too
ok, bye
hey, ok, you subtitude, then what?
was stoke for awhile, while working on it
oh ok same one so you substituted the x,y values in from the point they gave you then you solve for a, get it by itself
what i got right now 16=a(-1)(-1+3)(-1-1)
ok use PEMDAS do the parenthesis first (-1-1)^2 = (-2)^2 = 4
ok now you got, 16=a(-1)(4)
what happened to the (-1+3) ??
forogt..
8
yep good 16 = a(-1)(8)
16=-8a -2=a
we found a, now we must replace a with -2
correct now use that and put it back in the equation
to what equipon. 16=-2x(x+3)(x-1)^2?
the very first one now we put the x's and y's back in
?
f(x) = ax(x+3)(x-1)^2
just replace a with -2
-2a(1)(9) -18a
how you find the fourt root?
woah not x, replace a with -2 thats what we just solved for
??? fourth root of what
you looking for the fourt root
no its a fourth degree polynomial it just means our function has a x^4 term
ok, how you start then?
i dont know what you mean you just did it answer is f(x) = -2x(x+3)(x-1)^2
but the question is, find the fourt root
oh NOT
is find the fourt dree polynomial function
i thought all along,to find the fourt root
there are 3 real roots 0,-3,1
no really, their is four, 1 has multicplicity of 2
correct
ok thank, yoiu being great help to me,good night
:)

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