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anonymous
 5 years ago
prove the statement true :
1^2 +4^2 + 7^2 + ..... + (3n2)^2 = [n (6n^2  3n 1)] / 2
anonymous
 5 years ago
prove the statement true : 1^2 +4^2 + 7^2 + ..... + (3n2)^2 = [n (6n^2  3n 1)] / 2

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myininaya
 5 years ago
Best ResponseYou've already chosen the best response.1did you see my earlier reply to this?

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.1oh wait nvm ignore the early one do you know anything about induction?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0some1 tell me put n=1 and see both side equal , then that's proved

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0but when i try another n=2 then it s not equal

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.1for n=1 we have (3*12)^2=1^2=1 on lhs we have 1*(6*1^23*11)/2=2/2=1 on rhs so now we get to assume is true for k>=1 and now we have to show it is true for k+1

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.11^2+4^2+7^2+....+(3k2)^2+(3(k+1)2)^2 we want to show this equals the other side (whereever this is n we need k+1 to be there)

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.1so we know 1^2+4^2+...+(3k2)^2=k(6k^23k1)/2 so we have k[6k^23k1]/2+(3(k+1)2)^2 we need to manipulate this so that it is (k+1)*(6(k+1)^23(k+1)1)/2 ok? try to do this

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.1oh hello, n=2 it does work for n=2 we have on lhs 1^2+4^2=1+16=17 on rhs we have 2(6*2^23*21)/2=2461=17 so does work for n=2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0it wont work for the k+1 because the LHS ^ 2 and the RHS ^ 3 ? So can you explain more about this ? :<

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0let me try this again

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.1here i will scan what i did. you really have to know some algbra for this

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.1i added in alot of zeroes i forced it to be what i want and then the left overs canceled with the other left overs :)

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.1do you have any questions?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i got it now really appreciate for your help

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.1so you actually understood all the weird stuff i did? lol

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0no i did it another way and got the answer

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.1if i looked back on this, i would be like wtf

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.1lol i was trying to do it another way and i kept failing

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.1can you post what you did

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i dont know how to post the paper attaach in here , and i dont have the scan machine :(

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0but i will try to type it then
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