prove the statement true :
1^2 +4^2 + 7^2 + ..... + (3n-2)^2 = [n (6n^2 - 3n -1)] / 2

prove the statement true :
1^2 +4^2 + 7^2 + ..... + (3n-2)^2 = [n (6n^2 - 3n -1)] / 2

Hey! We 've verified this expert answer for you, click below to unlock the details :)

I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!

did you see my earlier reply to this?

i dont see it :(

oh wait nvm ignore the early one do you know anything about induction?

Looking for something else?

Not the answer you are looking for? Search for more explanations.

## More answers

Looking for something else?

Not the answer you are looking for? Search for more explanations.