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anonymous
 5 years ago
A car radiator contains 8 liters of a 32% antifreeze solution. How many liters of this solution should be drained and replaced with pure antifreeze to get a 49% solution?
anonymous
 5 years ago
A car radiator contains 8 liters of a 32% antifreeze solution. How many liters of this solution should be drained and replaced with pure antifreeze to get a 49% solution?

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0OKay so for this... damn it i have to go okay sorry bye!!

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0drain 8 liters of 32% and replace 8 liters of 49%

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0haha thats the lazy way :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0my only choices are 2 3 4 or 1.75 not 8

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0system of 2 equations Let x be 32% antifreeze, y is amount drained and replaced x+y = 8 .32x + y = .49

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0oops it should be 8*.49 use elimination subtract row 1  row 2 x + y = 8 .32x y = (8*.49) __________________ .64x +0 = 4.08 x = 4.08/.64 x = 6.375 y = 8x y = 86.375 y=1.625 1.625L should be drained and replaced

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0wierd i did something really wrong sorry answer is 2L
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