A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 5 years ago
solve using elimination method
0.3x0.2y=4
0.5x+0.5y=15/19
anonymous
 5 years ago
solve using elimination method 0.3x0.2y=4 0.5x+0.5y=15/19

This Question is Closed

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0panther77 didn't we just work on this one earlier?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i thought it was a different one but i may be wrong sorry

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i'll eliminate y in order to get the value of x you can also elimiate the x first. so i multiplied the first equation by 5 and multiplied the second equation by 2 1.5x  y = 20 x+ y = 30/19  + 2.5x = 20  30/19 2.5x= (38030)/19 2.5x = 350/19 x = 140/19 then plug the value of x into one of those equations to get the value of y

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0im sorry how would i figure y im unsure with the fractions?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0put the value of y to this equation 0.3x0.2y=4 you can substitute x with 140/19, as we've got x from elimination before. 0.3(140/19)  0.2y=4 or this 0.5x+0.5y=15/19 0.5(140/19)  0.5y = 15/19 yeah the fraction makes the calculation difficult. are you sure the second equation is 0.5x+0.5y=15/19? why dont you check your question again...

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok, then it's just a matter of calculation 0.5(140/19)  0.5y = 15/19 0.5y = (15/19)  (70/19) 0.5y=85/19 y=170/19
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.