At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
a + b = 18 a + c = 14
Hmm it's not what i am looking for....i am looking for (a+b+c)/3...arithmetic average of a,b and c..thnx anyway :)
i know but this is a starting point
ooh...right :) sorry :)
do we not have another equation? i only see two equations and 3 unknowns we need another equation if you a number that is known like because we can write the answer right now as (18+c)/3 or (32-a)/3 we can also write it in terms of b
no that's what we have...
so do you want the answer in terms of c, a, or b?
none of that...cause we have to find a integer....
how do you get c=5, anwar?
Anwar i's appreciate it if u'd explain that please.....
Well, since we will add them all up after all, we can choose any values if a,b and c that satisfy the two given equation \(a+b=18\) and \(a+c=14\). So choosing \(a=b=9\) would imply \(c=5\), then \((a+b+c)/3=23/3\).
Will u please forgive me...my classmate just e-mailed me and i have forgotten smth....b+c=8...soo sorry
This does not seem true :(
thats it, so myininaya was right :)
I think i can solve it by my own now...:) Thanks a lot..i appreciate it :):):)
ans anwarA u r just guessing the values, a+b=18. even if a=8 b=10
i found it....it's 8
What I said was totally wrong and stupid. :(
oh wait i made a mistake
(a+b)/2+(b+c)/2+(a+c)/2=9+8+7=24 2(a+b+c)/2=24 (a+b+c)/3=24/3=8 :)
this is how u do it :) thanks anyway :)
Oh you didn't give that \(b+c=8\) -.-
(b+c)/2=8...didn't i wrote this way?
a+b=18 a+c=14 ---------- b-c=4 b+c=8 -------- b=6 c=2 a=12 6+2+12/3
is the average of the two 8 or is b+c=8
How can we get b+c=8? Please explain
Guys..I'm soo sorry...it's morning....haven't had breakfast yet...so....it seems my brain isn't working well...:P So sorry...:(:(:(:(:(
the average of b+c=8
Going to eat...thnx :)
ok so 24/3=8 is correct gj because we get a=8 b=10 c=6 so (8+10+6)/3=8
a+b=18, a+c=14 and b+c=16 Hence, 2a+2b+2c=18+14+16=48 Or, a+b+c=24 Therefore, (a+b+c)=24/3=8
Thank you guys :)