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angela210793

  • 5 years ago

I need some help cause i have found a different no. not the 1 my classmates did...:S The arithmetic average of a and b is 9,the arithmetic average of a and c is 7.what is the arithmetic average of a,b and c?

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  1. anonymous
    • 5 years ago
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    a + b = 18 a + c = 14

  2. angela210793
    • 5 years ago
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    Hmm it's not what i am looking for....i am looking for (a+b+c)/3...arithmetic average of a,b and c..thnx anyway :)

  3. anonymous
    • 5 years ago
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    i know but this is a starting point

  4. angela210793
    • 5 years ago
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    ooh...right :) sorry :)

  5. myininaya
    • 5 years ago
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    do we not have another equation? i only see two equations and 3 unknowns we need another equation if you a number that is known like because we can write the answer right now as (18+c)/3 or (32-a)/3 we can also write it in terms of b

  6. angela210793
    • 5 years ago
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    no that's what we have...

  7. myininaya
    • 5 years ago
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    so do you want the answer in terms of c, a, or b?

  8. angela210793
    • 5 years ago
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    none of that...cause we have to find a integer....

  9. anonymous
    • 5 years ago
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    23/3

  10. myininaya
    • 5 years ago
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    how do you get c=5, anwar?

  11. angela210793
    • 5 years ago
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    Anwar i's appreciate it if u'd explain that please.....

  12. myininaya
    • 5 years ago
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    or a=9

  13. myininaya
    • 5 years ago
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    or b=9

  14. angela210793
    • 5 years ago
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    OMG!!!!!

  15. anonymous
    • 5 years ago
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    Well, since we will add them all up after all, we can choose any values if a,b and c that satisfy the two given equation \(a+b=18\) and \(a+c=14\). So choosing \(a=b=9\) would imply \(c=5\), then \((a+b+c)/3=23/3\).

  16. angela210793
    • 5 years ago
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    Will u please forgive me...my classmate just e-mailed me and i have forgotten smth....b+c=8...soo sorry

  17. anonymous
    • 5 years ago
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    This does not seem true :(

  18. anonymous
    • 5 years ago
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    thats it, so myininaya was right :)

  19. angela210793
    • 5 years ago
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    yea....

  20. angela210793
    • 5 years ago
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    I think i can solve it by my own now...:) Thanks a lot..i appreciate it :):):)

  21. anonymous
    • 5 years ago
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    ans anwarA u r just guessing the values, a+b=18. even if a=8 b=10

  22. angela210793
    • 5 years ago
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    i found it....it's 8

  23. myininaya
    • 5 years ago
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    22/3

  24. anonymous
    • 5 years ago
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    What I said was totally wrong and stupid. :(

  25. myininaya
    • 5 years ago
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    oh wait i made a mistake

  26. angela210793
    • 5 years ago
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    (a+b)/2+(b+c)/2+(a+c)/2=9+8+7=24 2(a+b+c)/2=24 (a+b+c)/3=24/3=8 :)

  27. angela210793
    • 5 years ago
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    this is how u do it :) thanks anyway :)

  28. anonymous
    • 5 years ago
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    Oh you didn't give that \(b+c=8\) -.-

  29. anonymous
    • 5 years ago
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    \((b+c)/2=8\)*

  30. angela210793
    • 5 years ago
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    (b+c)/2=8...didn't i wrote this way?

  31. anonymous
    • 5 years ago
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    a+b=18 a+c=14 ---------- b-c=4 b+c=8 -------- b=6 c=2 a=12 6+2+12/3

  32. myininaya
    • 5 years ago
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    is the average of the two 8 or is b+c=8

  33. anonymous
    • 5 years ago
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    How can we get b+c=8? Please explain

  34. angela210793
    • 5 years ago
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    Guys..I'm soo sorry...it's morning....haven't had breakfast yet...so....it seems my brain isn't working well...:P So sorry...:(:(:(:(:(

  35. angela210793
    • 5 years ago
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    the average of b+c=8

  36. angela210793
    • 5 years ago
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    Going to eat...thnx :)

  37. myininaya
    • 5 years ago
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    ok so 24/3=8 is correct gj because we get a=8 b=10 c=6 so (8+10+6)/3=8

  38. anonymous
    • 5 years ago
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    a+b=18, a+c=14 and b+c=16 Hence, 2a+2b+2c=18+14+16=48 Or, a+b+c=24 Therefore, (a+b+c)=24/3=8

  39. angela210793
    • 5 years ago
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    Thank you guys :)

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