I need some help cause i have found a different no. not the 1 my classmates did...:S
The arithmetic average of a and b is 9,the arithmetic average of a and c is 7.what is the arithmetic average of a,b and c?

- angela210793

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- anonymous

a + b = 18
a + c = 14

- angela210793

Hmm it's not what i am looking for....i am looking for (a+b+c)/3...arithmetic average of a,b and c..thnx anyway :)

- anonymous

i know but this is a starting point

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- angela210793

ooh...right :) sorry :)

- myininaya

do we not have another equation?
i only see two equations and 3 unknowns
we need another equation if you a number that is known
like because we can write the answer right now as (18+c)/3 or (32-a)/3
we can also write it in terms of b

- angela210793

no that's what we have...

- myininaya

so do you want the answer in terms of c, a, or b?

- angela210793

none of that...cause we have to find a integer....

- anonymous

23/3

- myininaya

how do you get c=5, anwar?

- angela210793

Anwar i's appreciate it if u'd explain that please.....

- myininaya

or a=9

- myininaya

or b=9

- angela210793

OMG!!!!!

- anonymous

Well, since we will add them all up after all, we can choose any values if a,b and c that satisfy the two given equation \(a+b=18\) and \(a+c=14\). So choosing \(a=b=9\) would imply \(c=5\), then \((a+b+c)/3=23/3\).

- angela210793

Will u please forgive me...my classmate just e-mailed me and i have forgotten smth....b+c=8...soo sorry

- anonymous

This does not seem true :(

- anonymous

thats it, so myininaya was right :)

- angela210793

yea....

- angela210793

I think i can solve it by my own now...:) Thanks a lot..i appreciate it :):):)

- anonymous

ans anwarA u r just guessing the values, a+b=18. even if a=8 b=10

- angela210793

i found it....it's 8

- myininaya

22/3

- anonymous

What I said was totally wrong and stupid. :(

- myininaya

oh wait i made a mistake

- angela210793

(a+b)/2+(b+c)/2+(a+c)/2=9+8+7=24
2(a+b+c)/2=24
(a+b+c)/3=24/3=8 :)

- angela210793

this is how u do it :) thanks anyway :)

- anonymous

Oh you didn't give that \(b+c=8\) -.-

- anonymous

\((b+c)/2=8\)*

- angela210793

(b+c)/2=8...didn't i wrote this way?

- anonymous

a+b=18
a+c=14
----------
b-c=4
b+c=8
--------
b=6
c=2
a=12
6+2+12/3

- myininaya

is the average of the two 8 or is b+c=8

- anonymous

How can we get b+c=8? Please explain

- angela210793

Guys..I'm soo sorry...it's morning....haven't had breakfast yet...so....it seems my brain isn't working well...:P So sorry...:(:(:(:(:(

- angela210793

the average of b+c=8

- angela210793

Going to eat...thnx :)

- myininaya

ok so 24/3=8 is correct gj
because we get a=8
b=10
c=6
so (8+10+6)/3=8

- anonymous

a+b=18, a+c=14 and b+c=16
Hence, 2a+2b+2c=18+14+16=48
Or, a+b+c=24
Therefore, (a+b+c)=24/3=8

- angela210793

Thank you guys :)

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