angela210793
  • angela210793
I need some help cause i have found a different no. not the 1 my classmates did...:S The arithmetic average of a and b is 9,the arithmetic average of a and c is 7.what is the arithmetic average of a,b and c?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
a + b = 18 a + c = 14
angela210793
  • angela210793
Hmm it's not what i am looking for....i am looking for (a+b+c)/3...arithmetic average of a,b and c..thnx anyway :)
anonymous
  • anonymous
i know but this is a starting point

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angela210793
  • angela210793
ooh...right :) sorry :)
myininaya
  • myininaya
do we not have another equation? i only see two equations and 3 unknowns we need another equation if you a number that is known like because we can write the answer right now as (18+c)/3 or (32-a)/3 we can also write it in terms of b
angela210793
  • angela210793
no that's what we have...
myininaya
  • myininaya
so do you want the answer in terms of c, a, or b?
angela210793
  • angela210793
none of that...cause we have to find a integer....
anonymous
  • anonymous
23/3
myininaya
  • myininaya
how do you get c=5, anwar?
angela210793
  • angela210793
Anwar i's appreciate it if u'd explain that please.....
myininaya
  • myininaya
or a=9
myininaya
  • myininaya
or b=9
angela210793
  • angela210793
OMG!!!!!
anonymous
  • anonymous
Well, since we will add them all up after all, we can choose any values if a,b and c that satisfy the two given equation \(a+b=18\) and \(a+c=14\). So choosing \(a=b=9\) would imply \(c=5\), then \((a+b+c)/3=23/3\).
angela210793
  • angela210793
Will u please forgive me...my classmate just e-mailed me and i have forgotten smth....b+c=8...soo sorry
anonymous
  • anonymous
This does not seem true :(
anonymous
  • anonymous
thats it, so myininaya was right :)
angela210793
  • angela210793
yea....
angela210793
  • angela210793
I think i can solve it by my own now...:) Thanks a lot..i appreciate it :):):)
anonymous
  • anonymous
ans anwarA u r just guessing the values, a+b=18. even if a=8 b=10
angela210793
  • angela210793
i found it....it's 8
myininaya
  • myininaya
22/3
anonymous
  • anonymous
What I said was totally wrong and stupid. :(
myininaya
  • myininaya
oh wait i made a mistake
angela210793
  • angela210793
(a+b)/2+(b+c)/2+(a+c)/2=9+8+7=24 2(a+b+c)/2=24 (a+b+c)/3=24/3=8 :)
angela210793
  • angela210793
this is how u do it :) thanks anyway :)
anonymous
  • anonymous
Oh you didn't give that \(b+c=8\) -.-
anonymous
  • anonymous
\((b+c)/2=8\)*
angela210793
  • angela210793
(b+c)/2=8...didn't i wrote this way?
anonymous
  • anonymous
a+b=18 a+c=14 ---------- b-c=4 b+c=8 -------- b=6 c=2 a=12 6+2+12/3
myininaya
  • myininaya
is the average of the two 8 or is b+c=8
anonymous
  • anonymous
How can we get b+c=8? Please explain
angela210793
  • angela210793
Guys..I'm soo sorry...it's morning....haven't had breakfast yet...so....it seems my brain isn't working well...:P So sorry...:(:(:(:(:(
angela210793
  • angela210793
the average of b+c=8
angela210793
  • angela210793
Going to eat...thnx :)
myininaya
  • myininaya
ok so 24/3=8 is correct gj because we get a=8 b=10 c=6 so (8+10+6)/3=8
anonymous
  • anonymous
a+b=18, a+c=14 and b+c=16 Hence, 2a+2b+2c=18+14+16=48 Or, a+b+c=24 Therefore, (a+b+c)=24/3=8
angela210793
  • angela210793
Thank you guys :)

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