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a + b = 18
a + c = 14

i know but this is a starting point

ooh...right :) sorry :)

no that's what we have...

so do you want the answer in terms of c, a, or b?

none of that...cause we have to find a integer....

23/3

how do you get c=5, anwar?

Anwar i's appreciate it if u'd explain that please.....

or a=9

or b=9

OMG!!!!!

This does not seem true :(

thats it, so myininaya was right :)

yea....

I think i can solve it by my own now...:) Thanks a lot..i appreciate it :):):)

ans anwarA u r just guessing the values, a+b=18. even if a=8 b=10

i found it....it's 8

22/3

What I said was totally wrong and stupid. :(

oh wait i made a mistake

(a+b)/2+(b+c)/2+(a+c)/2=9+8+7=24
2(a+b+c)/2=24
(a+b+c)/3=24/3=8 :)

this is how u do it :) thanks anyway :)

Oh you didn't give that \(b+c=8\) -.-

\((b+c)/2=8\)*

(b+c)/2=8...didn't i wrote this way?

a+b=18
a+c=14
----------
b-c=4
b+c=8
--------
b=6
c=2
a=12
6+2+12/3

is the average of the two 8 or is b+c=8

How can we get b+c=8? Please explain

the average of b+c=8

Going to eat...thnx :)

ok so 24/3=8 is correct gj
because we get a=8
b=10
c=6
so (8+10+6)/3=8

a+b=18, a+c=14 and b+c=16
Hence, 2a+2b+2c=18+14+16=48
Or, a+b+c=24
Therefore, (a+b+c)=24/3=8

Thank you guys :)