anonymous
  • anonymous
Bryce insists that (2+x)/8 is equivalent to (1+x)/4. What mistakes do you think is being made and how could you demonstrate to Bryce that the two expressions are not equivalent?
Mathematics
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SOLVED
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katieb
  • katieb
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myininaya
  • myininaya
(1+x)/4 *2/2=2(1+x)/4
myininaya
  • myininaya
oops that should be 8 on the bottm
myininaya
  • myininaya
(1+x)/4 *2/2=2(1+x)/8 2(1+x) is not the same as 2+x

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anonymous
  • anonymous
\[\frac{2+x}{8}=\frac{1+x}{4}\rightarrow \frac{8+4x}{8}=1+x \rightarrow 8+4x=8+8x \] \[4x=8x \rightarrow x=2x\] Which doesn't make sense since this says the variable x is equal to twice its value
myininaya
  • myininaya
they are only equal when x=0
anonymous
  • anonymous
That's true
myininaya
  • myininaya
you can also graph these two and show that they aren't the same line
anonymous
  • anonymous
you can do that as well
myininaya
  • myininaya
you can also show him a counterexample to his logic
myininaya
  • myininaya
by saying if we let x be 1 here what happens we ger 3/8 but over we get 2/4 2/4 does not equal to 3/8 sorry bryce
anonymous
  • anonymous
The math i did earlier covers all examples for any value of x, Which demonstrate that the two expressions are not equal when x is greater than or less than 0, it is only true when x=0 as myininaya stated earlier

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