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anonymous

  • 5 years ago

Bryce insists that (2+x)/8 is equivalent to (1+x)/4. What mistakes do you think is being made and how could you demonstrate to Bryce that the two expressions are not equivalent?

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  1. myininaya
    • 5 years ago
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    (1+x)/4 *2/2=2(1+x)/4

  2. myininaya
    • 5 years ago
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    oops that should be 8 on the bottm

  3. myininaya
    • 5 years ago
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    (1+x)/4 *2/2=2(1+x)/8 2(1+x) is not the same as 2+x

  4. anonymous
    • 5 years ago
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    \[\frac{2+x}{8}=\frac{1+x}{4}\rightarrow \frac{8+4x}{8}=1+x \rightarrow 8+4x=8+8x \] \[4x=8x \rightarrow x=2x\] Which doesn't make sense since this says the variable x is equal to twice its value

  5. myininaya
    • 5 years ago
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    they are only equal when x=0

  6. anonymous
    • 5 years ago
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    That's true

  7. myininaya
    • 5 years ago
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    you can also graph these two and show that they aren't the same line

  8. anonymous
    • 5 years ago
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    you can do that as well

  9. myininaya
    • 5 years ago
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    you can also show him a counterexample to his logic

  10. myininaya
    • 5 years ago
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    by saying if we let x be 1 here what happens we ger 3/8 but over we get 2/4 2/4 does not equal to 3/8 sorry bryce

  11. anonymous
    • 5 years ago
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    The math i did earlier covers all examples for any value of x, Which demonstrate that the two expressions are not equal when x is greater than or less than 0, it is only true when x=0 as myininaya stated earlier

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