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anonymous
 5 years ago
Find the sum of the geometric series.
5
Σ 2(4)k
k=1
anonymous
 5 years ago
Find the sum of the geometric series. 5 Σ 2(4)k k=1

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dumbcow
 5 years ago
Best ResponseYou've already chosen the best response.0is that (4)^k or (4)*k

dumbcow
 5 years ago
Best ResponseYou've already chosen the best response.0since its geometric, ill assume k is the exponent 2 is a constant so it can be pulled out of sum formula for sum of geometric sequence is \[s _{n}=\frac{a _{1}(1r ^{n})}{1r}\] r = 4, n =5, a=4 s = 4(1(4)^5)/(1(4)) s = 4(1+1024)/5 s = 820

dumbcow
 5 years ago
Best ResponseYou've already chosen the best response.0oops then multiply by 2 s = 820*2 s=1640

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0but wait a min, since it's a geometric series, you'lk have to take the absolute value of r , r = 4 = 4 >1, in this case, since R > 1 then the following series is said to diverge, right? ..
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