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anonymous
 5 years ago
3x^1/28x^1/43=0 Can you show me how to solve?
anonymous
 5 years ago
3x^1/28x^1/43=0 Can you show me how to solve?

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0solve the quadratic in y.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0You are to set up as a substitution problem and solve.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yes. solve 3y^28y3=0. lastly substitute x^(1/4) for y.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I came up with a substituion of u28u3=0 and came up with 4+square root 19 but I am not understanding how to substitute the original u=x1/4 and come up with the right answer

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0its not u^28u3=0 but 3u^28u3=0. if u came with something like u=4+sqrt(19). then x=u^4=(4+sqrt(19))^4. Thats it. :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Not exactly. You have to substitute back in the x 1/4 for the u. That is where I am stuck and not coming up with the correct answer.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0explain where you are stuck.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I solved the quadratics and got u=3,1/3. then x=3^4=81 or x=(1/3)^4=1/81.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0But x=1/81 does not satisfy the orginal eqn . so our ans is 81

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok. on the original problem I made u=x1/4. At this point the equation should have been 3u^28u3=0. I missed that, you were correct. At that point I plugged it in the quadratic equation. Bottom line I am coming up with 9, 1. So my substituion back should be x1/4=9 and x1/4=1. How do you solve these?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0why? x=9^4 or x=1 with ur values.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0it is x 1/4 = 9, x 1/4 =1

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0what is x1/4? Isnt it x^(1/4)?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Im sorry it is x^1/4 =9 and x^1/4 =1

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0let u=x^1/4 so that u^2 =x^1/2 3u^2  8u 3=0 using the quadratic formula u= [b+ sqrt(b^24ac)]/2a

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so where are u getting the problem? Raise both sides of the equality (x^1/4=9) to power 4. and u get x=9^4. Is this ur problem?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Yep Mark. That's what I did.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Suabhik, yes. that is my problem.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0is it x = 6561 and x=1?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Well alrighty then. Just talking it through really helped. Thanks saubhik!

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0hope u r clear with it. :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i better be. I have a test in an hour!

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok u= [(8)+ sqrt((8)^24(3)(3))]/2*3 u=[8+ sqrt(64+36)]/6 u={8+sqrt(100)/9 u= [8+10]/6 u= 18/6 =3 also the other u is 1/3

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Back again on this same question. Book says answer should be 81 and the extraneous is 1/81. How did they get there?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0u=x^1/4 =3 x=(3)^4=81

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0hope u get the procedure of getting it

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0and then by using the quadratic formula

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I got down to x^1/4=9 and x^1/4 =1. Was this correct? Then how did you come up with the 81, 1/81?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0No this is not correct. Please check ur equation.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0read the one i wrote on the top one and the second part

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0let u=x^1/4 so that u^2 =x^1/2 3u^2  8u 3=0 using the quadratic formula u= [b+ sqrt(b^24ac)]/2a u= [(8)+ sqrt((8)^24(3)(3))]/2*3 u=[8+ sqrt(64+36)]/6 u={8+sqrt(100)/9 u= [8+10]/6 u= 18/6 =3 also the other u is 1/3

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok. I can see how you got the 3, 1/3. I had made a mistake earlier in the problem.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0u=x^1/4 =3 x=(3)^4=81 u=(1/3)^4= 1/81

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Got it!!!! Thank you so much Mark!

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok welcome,,,,, saubnik also got it in his answer...

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok thnx....good luck with our exam

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Yep. I saw you both had it! Thanks again!
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