Hi, I was having some trouble with natural logarithms. Does anybody know how to solve [3^(2x)+4(3^(x+1)) = 189] for x using natural logarithms? I know it's a monster, sorry. :P

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Hi, I was having some trouble with natural logarithms. Does anybody know how to solve [3^(2x)+4(3^(x+1)) = 189] for x using natural logarithms? I know it's a monster, sorry. :P

Mathematics
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make substitution 3^x=y. It will be a quadratic.
Sorry, but would you mind explaining that to me? So I write 3^(2X) + 4y = 189, and then what?
No, the eqn will be y^2+4(3)y=189. Hope u can figure out why.:)

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Oh, I see! I think I can manage now. Thanks! :)
4the second term is 12 multiplied by 3 to the x
you let 3 raised to x be p, then you end up with a quadractic equation p squared plus tweleve p equals 189
p\[p ^{2}+12p=189\]

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