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anonymous
 5 years ago
find the equation of the following table of values:
t 0 1 2 3 4 5
v 1.5 1.3 1.4 2.0 2.4 2.7
where v is the velocity in m/s and t is time
anonymous
 5 years ago
find the equation of the following table of values: t 0 1 2 3 4 5 v 1.5 1.3 1.4 2.0 2.4 2.7 where v is the velocity in m/s and t is time

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amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1it might be quadratic, let me check...

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0how am i supposed to use it lol

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1well, since i designed it, i think its quite intuitive lol

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1you have places to put in your data points; a quad only needs 3 data points to figure out; .....

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1the "how many we need to find" box is for an additional 'x' data point to either test or determine

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1this data doesnt match precisely to a quad tho; its close, but not exact

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1i used the end points and the middle and asked it to determine the intermediates and it didnt match exactly

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i see could it be an exponential

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1with up to 5 points here, we could try to match it to an x^4 graph..... but yes, exponential is a likely possibility

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1no... not likely; the first and second and third points make a dip...

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1exponents dont dip lol

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1most likely a cubic ..... perhaps

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1i aint designed a cubic finder yet lol same principles; but with 4 poijts for reference and a new set of algorithms to figure out

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0no but i can write the whole question up if it clears anything

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1yes, all the info is better than just part of it :) you may have inadvertently left out some pertinent piece

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0An object is moving along the xaxis with values of the velocity v in m/s at time t given in the table above. Given that the distance traveled may be found by calculating the area under a velocity/time graph, use the trapezoidal rule to estimate the distance traveled by the particle in the first five seconds.

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1....... well then, lets use the trap rule lol

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yeah i intend on using the trapezoidal rule after finding the equation of the graph

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i think you need that first

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1why do the trap after finding an equation?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1the directions clearly sate; use this info and apply the trap rule... i see no need to complicate it :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0but you can use the trapezoidal rule without an equation i believe lol

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0actually wait i think im very wrong lol

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1the trap rule, as well as the simpson rule, and all the other numerical analysises are for estimating to a certain degree of precision what integration does with precision when you CANT integrate

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok wait let me attempt it i think i over complicated for no reason

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1oh theres a reason.. but thats best suited for openstudy psychology lol

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0omg i got the right answer im such an idiot

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1kinda paradoxal... your an idiot when you get the right answer ;)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0lol thanks for your help

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1youre quite welcome ;)
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