How do you write an equation in slope intercept form for a line that passes through a certain set of points? And how do you do it if they tell you the x intercept, but not the y intercept? Thanks!

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How do you write an equation in slope intercept form for a line that passes through a certain set of points? And how do you do it if they tell you the x intercept, but not the y intercept? Thanks!

Mathematics
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slope =(y2-y1)/(x2-x1) slope intercept form = y=mx+b
Ok, so you use the points in slope formula? But what if you're only given one set of points? Like if it said, slope -5, passes through (-3,-8) ? then how would you do the formula?
use formula, \[y-y_{1}=m(x-_x{1})\]

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m=-5 y1=-8 x1=-3
ok
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u need help with equation?
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Oh wait, what if it's perpendicular?
2 line intersect have angle 90 degree
paralell never intersect
Right, I know, so how would you put that in slope intercet equation?
slope -5, passes through (-3,-8) ?
No, if it says that it's perendicular to lik efor examle, y=3x-2
let do this ffrist y-(-8)=-5(x-(-3)) y+8= -5(x+3) y= -5x-15-8 y= -5x -23
Yes, I got that
u want write anothe equation is perendicular to this line y=3x-2?
yes, and passes through (6,-1)
perendicular slope is flip and opposite side Example : slope = -1/3 than y-(-1)=-1/3(x-6) \[y+1=\frac{-1}{3}( X)+2\]\[y=\frac{11x}{3}+2-1 \]\[y=\frac{-1x}{3}+1\] \[y=\frac{1x}{3}+1 \]perendicular to line y=3x-2 u can check by : produc of 2 slope is -1 then they are perendicular
Thanks!
\[\frac{-1}{3}\times3=-1\] -1 yes they are perendicular
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Thank you
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next it says 10
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