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anonymous

  • 5 years ago

13. Given the graph List all the even vertices. Please see atachment.

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  1. anonymous
    • 5 years ago
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  2. amistre64
    • 5 years ago
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    nothing appears on my screen

  3. anonymous
    • 5 years ago
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    I just opend it. so it does work.

  4. amistre64
    • 5 years ago
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    it opens for you, but not for me ....

  5. anonymous
    • 5 years ago
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    you don't have adobe 9 on your computer?

  6. amistre64
    • 5 years ago
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    prolly not, its a public library computer...

  7. anonymous
    • 5 years ago
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    ah

  8. anonymous
    • 5 years ago
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    try now

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  9. amistre64
    • 5 years ago
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    that one works :)

  10. amistre64
    • 5 years ago
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    now just have to determine what constitutes an 'even' vertice

  11. anonymous
    • 5 years ago
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    ok. this is where i don't understand

  12. amistre64
    • 5 years ago
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    me either yet, i think it means that the degree of the vertex is an even number, but gotta read a little more

  13. amistre64
    • 5 years ago
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    is this all the information that is given?

  14. anonymous
    • 5 years ago
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    vertices with even degree are even vertices, also those where a loop exists

  15. amistre64
    • 5 years ago
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    how can you determine an even degree vertice with no numbers present?

  16. anonymous
    • 5 years ago
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    A, B, D and E

  17. anonymous
    • 5 years ago
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    no of edges leaving a vertex is the degree

  18. anonymous
    • 5 years ago
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    its an undirected graph

  19. anonymous
    • 5 years ago
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    what do you mean uzma

  20. amistre64
    • 5 years ago
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    ahhh... so three lines connected is an odd then right?

  21. anonymous
    • 5 years ago
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    yes

  22. anonymous
    • 5 years ago
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    look ...there is a loop at vertex A, a loop contributes 2 to the degree, so A is an even vertex

  23. anonymous
    • 5 years ago
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    so then it woud be A B D and E like you said then?

  24. anonymous
    • 5 years ago
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    likewise there r 2 edges incident at B,degree 2 again even

  25. anonymous
    • 5 years ago
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    yeah

  26. anonymous
    • 5 years ago
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    ok. i get it now thank you.

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