find a third-degree polynomial equation with rational coefficants that has roots -4 and 2+i
Stacey Warren - Expert brainly.com
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it wants you to find a glorified fraction: that is equal to zero when you use those values
read rational in the wrong place.... its just a poly
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the 2 + i root means that there is a bend in the graph along the x=2 line, but that it is either above or below the graph ....
f'(2) = 0 would be a part of the equation i think
might be wrong tho ...
(x-1)^2 + 3 is a quadratic with roots at:
1 +- i sqrt(3) ; which means that its bend, its vertex, is along the x=1 line and that it is either above or below it.... so I am assuming that is a good analogy to this
the cubic formula tho is alot more complicated ..
(x+4)(x+4)(x - (2+i)) or (x+4)(x - (2+i))(x - (2+i)) seem to be the possibilities; lets try to find the products of these...