anonymous
  • anonymous
Train A & B are traveling in the same direction on parallel tracks. Train A is traveling at 40 mph & Train B at 48 mph. Train A passes a station at 2:20 am. If Train B passes the same station at 2:35 am, what time will Train A catch up to Train A?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
OOps, I meant train B catch up to train A
watchmath
  • watchmath
Train A leaves 15 minutes = 1/4 hour earlier than train B (from the station) After x hours the distance traveled by both train are Distance train A= (1/4)(40)+40x Distance train B= 48x Train B catch up train A if the two distance are equal \(10+40x=48x\) \(8x=10\) \(x=5/4\) hour = 1 hour 15 minutes So Train B catcch up Train A at 3:50 am
anonymous
  • anonymous
Thank you!

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watchmath
  • watchmath
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