## anonymous 5 years ago A coin is tossed twice. If heads comes up either time, we get $2. If heads does not come up, we lose$4. What is the expected value of this game?

1. anonymous

probability of getting at least one head on two tosses is $\frac{3}{4}$ and of getting no heads is $\frac{1}{4}$

2. anonymous

$E=2\times \frac{3}{4}-4\times \frac{1}{4}=\frac{6}{4}-\frac{4}{4}=\frac{2}{4}=\frac{1}{2}$

3. anonymous

or 50 cents. unless the problem meant you get \$2 for each head that comes up, but i did not read it that way.

4. anonymous

thanks

5. anonymous

welcome. E= what you get times probability you get it.