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anonymous

  • 5 years ago

Please help me find the roots of following polynomial equation: e^2x-5(e^2x)+6 = 0

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  1. amistre64
    • 5 years ago
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    is that a typo? I dont think there is a '2' in the middle term..

  2. anonymous
    • 5 years ago
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    Its not a typo.Its from our exam paper.

  3. angela210793
    • 5 years ago
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    @amistre64...May you please,please,please see my problem? Please??????? :)

  4. amistre64
    • 5 years ago
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    then combine like terms ..... a = e^2x -4a+6 = 0 a = 6/4 = 3/2 e^2x = 3/2 2x = ln(3/2) x = ln(3/2)/2

  5. amistre64
    • 5 years ago
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    if i can find it ;)

  6. angela210793
    • 5 years ago
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    perhaps it is in my profile...try 2 click once there :)

  7. anonymous
    • 5 years ago
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    I am not getting your solution. Can you please explain?

  8. amistre64
    • 5 years ago
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    not getting as you dont follow it? or the answer is wrong?

  9. anonymous
    • 5 years ago
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    I do not follow it.Its kinda tough.

  10. anonymous
    • 5 years ago
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    pleasse come back later to my question, dont quite understand what you mean

  11. amistre64
    • 5 years ago
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    e^2x can be substituted for becasue it doesnt change in the problem; its an unknown that we determine; so to clean up the equation, make it = a and use 'a' instead. a -5a +6 =0 -4a +6 = 0 -4a = -6 a = -6/-4 = 6/4 = 3/2

  12. amistre64
    • 5 years ago
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    ok :)

  13. amistre64
    • 5 years ago
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    since e^2x = a ; we told it to ... e^2x = 3/2 we solve for x by using logarithmic properties.. ln(e^2x) = ln(3/2) 2x = ln(3/2) x = ln(3/2) ------ 2

  14. anonymous
    • 5 years ago
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    Its involved I guess.I would look into it.Thanks for your help.I appreciate it.

  15. amistre64
    • 5 years ago
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    your welcome But I really think that this could have been a typo; which would make this part easier: a = e^x a^2 -5a +6 = 0 (a-6)(a+1) = 0 a = 6 and a = -1 e^x = a e^x = 6 ; x = ln(6) e^x = -1, which is impossible so disregard the -1 x = ln(6)

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