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anonymous
 5 years ago
Hey can someone please explain to me how to figure out how to match slope fields to their graphs without the use of a calculator? for problem such as these: y'=y b) y'=xy c) y'=1/y
anonymous
 5 years ago
Hey can someone please explain to me how to figure out how to match slope fields to their graphs without the use of a calculator? for problem such as these: y'=y b) y'=xy c) y'=1/y

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watchmath
 5 years ago
Best ResponseYou've already chosen the best response.1It really depends on how the give choice are look like. We can always try to extract some special feature of each equatio. For example for \(y]=y\) we know that when \(y=0\) we have \(y'=0\). So along the xaxis the slope fields are horizontal line segments. But it is possible that the other graph has this feature. Then for example you look at \(y=1\). Here \(y'=1\). So along the line \(y=1\) the slopes are all 1 and so on...

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0no my question is how do you test for conditional convergence and absolute convergence

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0please ignore the previous comment . so we plug zero in for y' zero

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0can you please explain how to do it for y'=1/y

watchmath
 5 years ago
Best ResponseYou've already chosen the best response.1for y'=1/y for example we can see that for y=0 the slope is undefined. So along the xaxis there is no slope field

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so we plug zero in for y ?

watchmath
 5 years ago
Best ResponseYou've already chosen the best response.1yes, but 1/0 is undefined.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0but what i dont understand is my teacher wrote on the board for this problem y=0 y>0 y'= undefined y'>0 do you know how she came up with the inequality part

watchmath
 5 years ago
Best ResponseYou've already chosen the best response.1I think what your techer meant was y' is undefined for y=0. And y' >0 for y>0

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0do you know how she came up with that

watchmath
 5 years ago
Best ResponseYou've already chosen the best response.1well, if y>0, then 1/y >0. Since y'=1/y. Then y' >0 too.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so you have to look at each quadrant on the graph to figure it out

watchmath
 5 years ago
Best ResponseYou've already chosen the best response.1Since this is about matching as I said earlier it depends on the given choices. Maybe by just analyzing for y>0 it is enough to see the the behavior of the right graph. If it is not enough my by you need an analysis for y<0. But basically you just plug in some certain values of y (or x) so that you can see a property that the right graph has but the others are not.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0okay . how would you do it for y'=x

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0would you say x=0 and y'=0

watchmath
 5 years ago
Best ResponseYou've already chosen the best response.1yes, for x=0 we have y'=0. But the other slope field might be has this feature too. So you need to look at for something else in that case. Say plug in x=1 to get y'=1. If the other slope field also have this feature then you need to look at for something else... and so on....

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so on the y axis you have horizontal lines got through it

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i wanted to check with you one more so if you y'=4y . you plugin zero for y an you get y=0 , y'=4

watchmath
 5 years ago
Best ResponseYou've already chosen the best response.1yes, but maybe the slope of 4 is not very easy to see. So instead plug in y=4 to get y'=0.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0okay i see so you can plug in whatever you want

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0also, if you want to check based on quadrants so the for example you explained to me y'=y you could say when y>0 ,y'> 0

watchmath
 5 years ago
Best ResponseYou've already chosen the best response.1yes, you can do that as well :).

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0hey do you think i can ask you another question because you have been very helpful

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0hey do you think i can ask you another question because you have been very helpful
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