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anonymous

  • 5 years ago

how to describe vertical asymptotes and holes for the graph y= (x-2)(x+4)/(x+4)(x+5)

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  1. amistre64
    • 5 years ago
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    holes occur at the points that the top and bottom cancel: (x+4) ----- in this case; there is a hole at x = -4 (x+4) VAs occur when you cant cancel; which in this case is x = -5

  2. anonymous
    • 5 years ago
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    why wouldnt the (x-2) be a asymtote?

  3. amistre64
    • 5 years ago
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    x-2 makes 0 up top which is perfectly acceptable; asmps and holes are were the domain is undefined

  4. amistre64
    • 5 years ago
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    0/# is fine #/0 is bad; #/0 is either a asymp or a hole

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